Why doesn't code like the following catch CTRL-C?
MAXVAL = 10000
STEP_INTERVAL = 10
for i in range(1, MAXVAL, STEP_INTERVAL):
try:
print str(i)
except KeyboardInterrupt:
break
print "done"
My expectation is -- if CTRL-C is pressed while program is running, KeyboardInterrupt is supposed to leave the loop. It does not.
Any help on what I'm doing wrong?
code flow is as follows:
for grabs new object from list (generated by range) and sets i to ittryprint1If you hit CTRL-C in the part 1 it is outside the try/except, so it won't catch the exception.
Try this instead:
MaxVal = 10000
StepInterval = 10
try:
for i in range(1, MaxVal, StepInterval):
print i
except KeyboardInterrupt:
pass
print "done"
print statement inside the except clause, then it will be printed only when pressing ctrl-c and not when the for-loop finishes normally. Exceptions can be just pass when they are expected, and you want to just ignore then, and do nothing about it. It is a valid approach, as long as you know what you're ignoring. I would say bare except without specifing a exception class is bad, but pass is fine.I was having this same problem and I just found out what was the solution:
You're running this code in an IDE like PyCharm. The IDE is taking ctrl+c (keyboardinterrupt) as copy. Try running your code in the terminal.
