I have the following string:
string1 = "1/0/1/A1,A2"
string2 = "1/1/A1,A2"
string3 = "0/A1,A2"
In the above strings I have to replace the character with zero if it does not exist. The default structure will be "number/number/number/any_character`", if any of number is missing It has to replace with zero. The answer will be as follows.
print(string1) = "1/0/1/A1,A2"
print(string2) = "1/1/0/A1,A2"
print(string3) = "0/0/0/A1,A2"
You can use str.split:
def pad_string(_input, _add='0'):
*_vals, _str = _input.split('/')
return '/'.join([*_vals, *([_add]*(3-len(_vals))), _str])
results = list(map(pad_string, ['1/0/1/A1,A2', '1/1/A1,A2', '0/A1,A2']))
Output:
['1/0/1/A1,A2', '1/1/0/A1,A2', '0/0/0/A1,A2']
You can easily fill missing elements from the left:
def fillZeros(item):
chunks = item.split('/')
for inserts in range(0, 4 - len(chunks)):
chunks.insert(0, '0')
return '/'.join(chunks)
string1 = "1/0/1/A1,A2"
string2 = "1/1/A1,A2"
string3 = "0/A1,A2"
for myString in (string1, string2, string3):
print fillZeros(myString)
Prints:
1/0/1/A1,A2
0/1/1/A1,A2
0/0/0/A1,A2
But for you string2 example you need to identify which element is missing: 1/1/A1,A2. Is the first or the third element missing ?!
If you want to use just string manipulation and loops, try this
strings_list = []
for string in [string1, string2, string3]: # make list containing all strings
strings_list.append(string)
new_strings = [] # make list containing the new strings
for string in strings_list:
if string.count("0/") + string.count("1/") == 3:
# identify the strings not missing a number
new_strings.append(string)
if string.count("0/") + string.count("1/") == 2:
# identify the strings missing 1 number
string = string[:4] + "0/" + string[4:]
new_strings.append(string)
if string.count("0/") + string.count("1/") == 1:
# identify the strings missing 2 numbers
string = string[:2] + "0/" + string[2:]
new_strings.append(string)
print(new_strings)
This results in ['1/0/1/A1,A2', '1/1/0/A1,A2', '0/0/A1,A2'].
