comparing two string lists and check if they have at least one same string

Question

I'm trying to compare two String list with each other and check if at least the have one exact same string or not ..

For example:

List<String> list1 = ['1','2','3','4'];

List<String> list2 = ['1','5','6','7'];

In this case I will do action cause both have same string which is 1, and it could be more than one exact same string and the action will be the same.

But if they don't have any similar strings then I will do another action.

How can I do something like this?

@MatthewPage of course i know! but this doesn't work with looping :) — lamatat
– lamatat, Commented Jan 28, 2019 at 12:22

Albert221 · Accepted Answer · 2019-01-28 12:14:42Z

20

You can do it with any() and contains() method:

if (list1.any((item) => list2.contains(item))) {
    // Lists have at least one common element
} else {
    // Lists DON'T have any common element
}

answered Jan 28, 2019 at 12:14

Albert221

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3 Comments

lamatat Over a year ago

Thank you so much!

Albert221 Over a year ago

@lamatat if you found an answer helpful and it resolves your issue, please accept the answer :)

lamatat Over a year ago

both answers are helpful and working and answered the same time .. i don't know to accept which so i uovoted both lol

Günter Zöchbauer · Accepted Answer · 2019-01-28 12:13:20Z

9

Set has an intersection that does that:

list1.toSet().intersection(list2.toSet()).length > 0

answered Jan 28, 2019 at 12:13

Günter Zöchbauer

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2 Comments

Günter Zöchbauer Over a year ago

stackoverflow.com/questions/10404516/… mentions some other handy features to compare lists or iterables (not directly related to the question though)

lrn Over a year ago

Instead of converting both to sets, you can als just do list1.any(list2.toSet().contains).

iDecode · Accepted Answer · 2022-11-30 14:45:28Z

0

A shorter version:

bool hasCommonElement = list1.any(list2.contains);

answered Nov 30, 2022 at 14:45

iDecode

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