Char pointer assignment segment fault

Question

#include <stdio.h>
#include <stdlib.h>
int main(){
 char *str="abcdce";
 char c='c';
 char *pfast=str,*pslow=str;
 while(*pfast!='\0'){
     if(*pfast==c){
       pfast++;
       *pslow=*pfast; //error here when pfast reaches the first 'c'
     }
    pfast++;
    pslow++;
 }
 *pslow='\0';
 return 0;
}

segment fault when it runs to the assignment statement of "*pslow=*pfast;"...

Somebody tell me why, thanks in advance!

Did you mean™ pslow=pfast;?

Federico klez Culloca
– Federico klez Culloca

2011-03-26 13:07:31 +00:00
Commented Mar 26, 2011 at 13:07 — Federico klez Culloca
– Federico klez Culloca, Commented Mar 26, 2011 at 13:07

codaddict · Accepted Answer · 2011-03-26 13:07:16Z

8

You are trying to change a string literal which leads to undefined behavior.

Change

char *str="abcdce";

to

char str[] ="abcdce";

answered Mar 26, 2011 at 13:07

codaddict

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1 Comment

codaddict Over a year ago

@witmusk: You are welcome. Since you are new and have not accepted answers to any of the questions you've asked so far, I would like to tell you that you can mark the answer that helped you to solve the problem by clicking the right mark next to the answer.

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