Combining two objects in JavaScript?

Question

I have two JSON files.

one looks like this:

    {
base: "EUR",
date: "2019-01-30",

rates: {

    USD: 1.1429,
    AND MORE....
    ...
    ...

}
}

and another one that looks like this:

{
results: {
USD: {
    currencyName: "United States Dollar",
    currencySymbol: "$",
    id: "USD"
}
}

I want to combine them together and get an object that looks like this:

{
results: {
USD: {
    currencyName: "United States Dollar",
    currencySymbol: "$",
    id: "USD",
    value: 1.1429   <====== the change
}
}

I couldn't find anything similar here... and have no idea how to begin

I am getting the values from these links:

https://free.currencyconverterapi.com/api/v6/currencies

https://api.exchangeratesapi.io/latest

with fetch function:

function getdataFromApiAsync() {
  return fetch('https://api.exchangeratesapi.io/latest')
    .then((response) => response.json())
    .then((responseJson) => {
      return responseJson.rates;
    })
    .catch((error) => {
      console.error(error);
    });
}

so you have to loop over the one and add it to the other.... going to be loops.... — epascarello
– epascarello, Commented Jan 30, 2019 at 17:12
What you posted as "JSON" is not JSON at all. There's no such thing as a "JSON Object" — Randy Casburn
– Randy Casburn, Commented Jan 30, 2019 at 17:13
As epascarello points out - loop over one and add it to the other. Best of luck to you. — Randy Casburn
– Randy Casburn, Commented Jan 30, 2019 at 17:21

Scrimothy · Accepted Answer · 2019-01-30 17:32:41Z

1

Assuming that your results object has an interface sort of like this:

{
  [key: string]: {
    currencyName: string;
    currencySymbol: string;
    id: string;
    value?: number;
  }
}

where the id here always matches to a key of the rates object, then you would probably want to loop through the values of this results object and add a value from the other object's rates, like this:

Object.values(results).forEach(result => {
  const value = rates[result.id];
  if (value) {
    result.value = value;
  }
});

answered Jan 30, 2019 at 17:32

Scrimothy

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