Secure, automated, login for selenium with python

Question

I am writing test cases using selenium in python for a website, and am having trouble finding the best way to pass a correct login for each scenario. Currently I am using a wait and manually typing in the account information every time:

@given('I wait for input of correct credentials')
    def step_impl(context):
        WebDriverWait(context.driver, 20).until( 
             expected_conditions.visibility_of_elements_located(
                BasePageLocators.SIDEBAR)
        )

Is there a better way without having to send the information in my code? Preferably one that involves no manual input

JeffC · Accepted Answer · 2019-01-31 17:59:11Z

3

While this article was written specifically to address how to handle SauceLabs-related creds, there's no reason you can't use the same method.

You take the credentials and store it outside of your code, e.g. in a Windows Environment variable, some local file, or the like. That way people with access to your repo don't have access to your credentials. It also allows each user to set up their own local credentials so that everyone can use their own credentials without modifying the scripts.

answered Jan 31, 2019 at 17:59

JeffC

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undetected Selenium · Accepted Answer · 2019-01-31 15:50:55Z

0

You can invoke send_keys() method directly once the WebDriverWait returns the element as follows:

WebDriverWait(context.driver, 20).until( 
    expected_conditions.visibility_of_elements_located(
        BasePageLocators.SIDEBAR).send_keys("Allan Blackmar")

answered Jan 31, 2019 at 15:50

undetected Selenium

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3 Comments

Corey Goldberg Over a year ago

how does this answer the question? The question asked about securely passing credentials without specifying them in code.

JeffC Over a year ago

@CoreyGoldberg While I agree with you, I don't think the question is super clear what the actual issue is.

Corey Goldberg Over a year ago

@JeffC the question isn't super clear, but it's clear enough to know this answer isn't related whatsoever

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