Passing arguments to a shell script via stdin multiple times

Question

I have a script StartProcess.sh that accepts two options in stdin - 3 and a filename test.xml.

If I run the below script, it executes correctly, and waits again for the input. I want someway to pass 3 and test.xml n times to StartProcess.sh. How do I achieve this.

./StartProcess.sh << STDIN -o other --options 
3
test.xml
STDIN

Inian · Accepted Answer · 2019-02-01 04:47:50Z

1

You can run a loop to pass the arguments as many times in a loop and run a script over a pipe-line. That way, the script is just launched once and the arguments gets sent over stdin any number of times of your choice

count=3
for (( iter = 0; iter < 3; iter++ )); do
    echo "3" "test.xml"
done | StartProcess.sh

But I'm not fully sure if you wanted to pass the literal string test.xml as an argument or the content of the file.

edited Feb 1, 2019 at 4:47

answered Feb 1, 2019 at 4:24

Inian

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