python replace string ignore new line

Question

For example ,

str="dddabc
d
e
xxxx
123
345"

,want to replace "abcde" with null . New str need to be

"ddd
xxxx
123
345"

What is the easy way to do it ?

If I drop the new line , the new string will be dddxxxx123345 , and that wrong

This need to be on linux so it \r\n maybe

Albin Paul · Accepted Answer · 2019-02-06 14:27:01Z

3

Use regex re.sub

Return the string obtained by replacing the leftmost non-overlapping occurrences of pattern in string by the replacement repl. If the pattern isn’t found, string is returned unchanged. repl can be a string or a function; if it is a string, any backslash escapes in it are processed.

import re
st="""dddabc
d
e
xxxx
123
345
"""
rep="abcde"
print(re.sub(r'\n?'.join(rep),r'',st))

OUTPUT

ddd
xxxx
123
345

edited Feb 6, 2019 at 14:27

answered Feb 6, 2019 at 11:21

Albin Paul

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3 Comments

Albin Paul Over a year ago

@devohourse I have made the changes , earlier I didnt use raw strings now I did. That caused the error :-).

devohourse Over a year ago

that but wtill I get same error , maybe because that need to work on linux and there break line is \r\n ?

Albin Paul Over a year ago

@devohourse line break is always \n now if you are unsure about this type print(repr(string)) to print the underlying representation

Spoutnovitch · Accepted Answer · 2019-02-06 11:19:33Z

1

Use regex as so :

new_str = re.sub('a(\s)*b(\s)*c(\s)*d(\s)*e(\s)*', "", str)

answered Feb 6, 2019 at 11:19

Spoutnovitch

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