Have objects in laravel:
use AAA;
use BBB;
use CCC;
...
From input getting the name: "AAA...";
$from_input = $some_input;
can I accomplish this:
$obj = new $from_input;
return $obj::where('status', 1)->get();
"new" function cannot find the class "AAA"
strval not helping. Please advice.
Security Notice Due to the insecurity of allowing an end user to instantiate any class through this method, I highly recommend against doing this and following my example at the bottom.
Class imports are not evaluated at runtime. You'd have to use the full path to the class to dynamically instantiate it as illustrated in this example:
<?php
namespace One {
use Two\B;
class A {
function __construct($className) {
echo "Attempting to construct $className..";
new $className;
}
}
new A(B::class); // Works since the B import is evaluated before runtime.
try {
new A("B"); // Doesn't work since "B" is not evaluated until runtime
}
catch (\Throwable $e) {
echo $e->getMessage() . "\n";
}
new A("Two\B"); // Works since you use the full path to B.
}
namespace Two {
class B {
function __construct() {
echo "B constructed!\n";
}
}
}
While you could do this, that's asking for trouble. What would stop someone from retrieving data out of some model they shouldn't have access to?
Instead, build up an array of available classes and let them pass the array key instead of passing the name of the class.
$classes = [
'a' => AAA::class,
'b' => BBB::class,
'c' => CCC::class,
];
// $from_input being a, b, or c
if (isset($classes[$from_input])) {
$obj = new $classes[$from_input];
}
::class is just a keyword that gives the full name of the class, you shouldn't use ::class as a string like in your example.use is not going to be evaluated at runtime. You'd need to use the full path to the class: 3v4l.org/7ABSEYou could invoke the IoC container which will build you the object with any injected dependencies.
$obj = app()->make($from_input)
or simply
$obj = app($from_input)
use AAA; so it should be found. Maybe AAA is not properly namespaced.