Need to get substring from string in bash

Question

I'm trying to get Atom version in bash. Thid regex is working, but I need a substring from string, which giving grep. How can I get version from this string?

<span class="version">1.34.0</span>

curl https://atom.io/ | grep 'class="version"' | grep '[0-9]\+.[0-9]\+.[0-9]\+'

Note if you have Gnu grep you can use the -P option for perl-style regex's and the -o option to print only what matches the pattern. Try this as your last command in the pipeline:grep -oP "\d+\.\d+\.\d+" Oh and notice escaping the dot for a literal dot, otherwise it means any character. — Gary_W
– Gary_W, Commented Feb 8, 2019 at 22:14

karakfa · Accepted Answer · 2019-02-08 21:47:03Z

2

with awk

$ curl ... | awk -F'[<>]' '/class="version"/{print $3; exit}'

answered Feb 8, 2019 at 21:47

karakfa

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jonroethke · Accepted Answer · 2019-02-08 21:20:20Z

0

You can achieve this by using the cut command and adding your respective delimiters; in your case this would be the > and < tags encapsulating the version.

Input:

curl -s https://atom.io/ \
| grep 'class="version"' \
| grep '[0-9]\+.[0-9]\+.[0-9]\+' \
| cut -d '>' -f2 \
| cut -d '<' -f1

Output:

1.34.0

*added the curl -s flag to make output silent, personal choice

answered Feb 8, 2019 at 21:20

jonroethke

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