How can I combine multiple updates to a numpy array in one line of code?

Question

This is an odd question to phrase, but here's my code:

weights[0] = weights[0] - (1 / outputY.size) * alpha * (errorDiff) * normalizedX[i][0]
weights[1] = weights[1] - (1 / outputY.size) * alpha * (errorDiff) * normalizedX[i][1]
weights[2] = weights[2] - (1 / outputY.size) * alpha * (errorDiff) * normalizedX[i][2]

Where weights and normalizedX are numpy arrays. Is there someway to do that in one line rather than repeat it? Alternatively, I could use a loop, but I'm wondering if there's a more elegant way first.

You can do a list comprehension of sorts by putting the foot loop between brackets, but it probably wouldn’t look that elegant. — Jack Moody
– Jack Moody, Commented Feb 10, 2019 at 16:27

Guillaume Ramé · Accepted Answer · 2019-02-10 16:31:01Z

5

Assuming weights has dimensions (3,) and normalised is (n, 3):

weights = weights - (1 / outputY.size) * alpha * (errorDiff) * normalizedX[i]

You can also do this in place:

weights -= (1 / outputY.size) * alpha * (errorDiff) * normalizedX[i]

answered Feb 10, 2019 at 16:31

Guillaume Ramé

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