Getting TypeError when wrapping input().split() in int()

Question

So I just wanted to know the reason and cause of error I am getting in order to get a better understanding of python.

Here is what I have tried.

Code snippet #1

x,y=int(input()),int(input())
print(x,y)
print(type(x))
print(type(y))

So I get the output -

4
6
4 6
<class 'int'>
<class 'int'>

I am fine with the output, but what bugs me is why I can't use it in the manner like -

Code snippet #2

x,y= int(input().split('-'))
print(x,y)
print(type(x))
print(type(y))

So here, on wrapping input().split() inside int(), it throws an error as :

TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'

My Doubt

I just want to know why I cannot wrap int() inside input().split() ? Is there an alternate way to do it? Or if it's not allowed please explain why.

Because split returns a list. You can't cast list to int. You should use list comprehension or map to make it work. — user2956272
– user2956272, Commented Feb 12, 2019 at 7:15
@dyukha you are correct. I just came across the concept of map and found what you said. — shuberman
– shuberman, Commented Feb 12, 2019 at 7:17

Partho63 · Accepted Answer · 2019-02-12 07:22:27Z

2

From docs.python.org:

str.split() returns a list of the words in str

You can not turn a list to a int

You can try this way:

(x, y) = (int(x) for x in input().split('-'))
print(x, y)
print(type(x))
print(type(y))

answered Feb 12, 2019 at 7:22

Partho63

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1 Comment

shuberman Over a year ago

Your solution is also acceptable and an alternate way to get the job done.Appreciate your help.

shuberman · Accepted Answer · 2019-02-12 07:22:28Z

1

Okay so if you want to take multiple inputs in a single line and also convert it into desired data type, you can use map() to achieve it.

Code snippet #3

x,y,z=map(int,input().strip().split())
print(x,y,z)
print(type(x))
print(type(y))
print(type(z))

So your output will look like this -

2 3 4
2 3 4
<class 'int'>
<class 'int'>
<class 'int'>

And as @dyukha pointed out correctly the reason you cannot wrap input().split() inside int() is because split() returns a list and we cannot cast list to int data type.

answered Feb 12, 2019 at 7:22

shuberman

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