Using PHP preg_replace to replace a value between two strings

Question

I have a script that pulls in some HTML to my webpage in the form of a table. I would like to replace part of a URL contained within the HTML using PHP preg_replace. The URL contains some text which is always different. The URL is not unique in the webpage, but the one I want to replace ONLY appears before a specific image.

My (non working, laughable and probably completely wrong) attempt so far is as follows:

$result = preg_replace( '/\http://www.mysite.com/script.php?&variable=1.*\<img src="http://www.mysite.com/images/image.gif"', 'http://www.mysite.com/script.php?.*\<img src="http://www.mysite.com/images/image.gif"', $result );

The above example attempts to remove &variable=1 from a single URL on the page. The URL appears many times on the page, but only once directly before image.gif. The part of the URL that is always different is represented by .*\ to match anything.

Can anybody produce a working example? Thanks!

Mike C · Accepted Answer · 2011-03-29 14:23:25Z

1

I think you're pretty close but you forgot a few technical things like using delimiters around the regex (the '|' in the example below) and using references ($1 and $2 below). If the code below doesn't work please post an example of the text you're trying to match.

 $result = preg_replace('|http://www.mysite.com/script.php\?([^"]*)&variable=1([^<]*)<img src="http://www.mysite.com/images/image.gif"|', 'http://www.mysite.com/script.php?$1$2<img src="http://www.mysite.com/images/image.gif"', $result );

answered Mar 29, 2011 at 14:23

Mike C

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