Window.open() without url path where I called the function

Question

I've one problem with window.open() function.

I need to open each domain from this list and check if it's pointed to a lander.

I tried to get all domains with document.querySelectorAll... well, it doesn't matter.

When I calling function window.open(domain, '_blank') - it's always point to this url: brandnames.net/domain But I need only url to be as: google.com , not brandnames.net/google.com ( for example ).

As I understand window.open() - gives absolute path before (domain argument) - how I can to avoid this?

may be domain root path settled to brandnames.net/shop by using proxy server or .htaccess file (redirect rules) that's why if you want to access brandnames.net but it is redirecting to brandnames.net/shop automatically — Mahamudul Hasan
– Mahamudul Hasan, Commented Feb 17, 2019 at 8:01

hoangdv · Accepted Answer · 2019-02-17 08:04:02Z

1

Try call window.open with a full protocol domain.

window.open('google.com', '_blank') // => Go to brandnames.net/google.com

window.open('https://google.com', '_blank') // => Go to https://google.com

answered Feb 17, 2019 at 8:04

hoangdv

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