Calling a function within a function and passing its arguments (*args) - Python

Question

I don't see myself that bad in python but I am struggling to figure out what it is wrong in my code.

import numpy as np

x = np.array([[1, 2], [3, 4]])

def func1(x, params, *args):
    x = x.T
    if args[0] == 'condition':
        params['parameter1'] = False
        args = args[1:]
    else:
        params['parameter1'] = True
    return x, params

def func2(x, *args):
    params = {}
    params['parameter1'] = True
    params['parameter2'] = 'solid'
    params['parameter3'] = 200
    x, params = func1(x, params, args[:])
    print(params)
    print(x)
    print(args)

func2(x, 'condition')

The problem I am facing is that the "if" in func1 is not executed. Python does not see that args[0] is equal to the string 'condition' despite that I clearly pass it when calling the func2 on the last line. Despite that we I print the length of args before If-statement, I get 1 as an indication that there is indeed an argument "condition" being passed.

print(len(args)) *# gives 1*

I will appreciate your feedback. Thank you in advance.

First and last step of debugging: Add a print(args) to your func1 function. — Aran-Fey
– Aran-Fey, Commented Feb 22, 2019 at 12:40

markuscosinus · Accepted Answer · 2019-02-22 12:38:59Z

1

Try replacing

x, params = func1(x, params, args[:])

with

x, params = func1(x, params, *args)

If you do not use the * the value that is stored in args in func1 will be (('condition',),) instead of ('condition',). Thats also why print(len(args)) still gives one as output.

answered Feb 22, 2019 at 12:38

markuscosinus

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2 Comments

Baraa Over a year ago

Thank you for your quick response. It didn't do the trick unfortunately. I am expecting to re-set the parameter1 in the dictionary to "False". But it still gives me "True".

markuscosinus Over a year ago

I also tried to run it and it gives me False. Maybe you changed something else during your error search?

Dmitry Grachev · Accepted Answer · 2019-02-22 13:07:42Z

1

In func2(x, *args): you must use

x, params = func1(x, params, *args)

If you use args[:], then you get dict(dict(args)) type object.

answered Feb 22, 2019 at 13:07

Dmitry Grachev

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1 Comment

Baraa Over a year ago

Thank you Dmitry for the illustration :*

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