How to change values in an array in an efficient way

Question

I am getting the following arrays from external api endpoint.

Input:-

1. [["date", "country_name", "month"], ["2019-02-21", "US", "Jan"]]
2. ["name", "homeAddress", "zipcode"]

Expected Output:-

1. [["Date", "Country Name", "Month"], ["2019-02-21", "US", "Jan"]]
2. ["Name", "Home Address", "Zipcode"]

How can I change the each array in an efficient way in Ruby on Rails?

Update: Some of the name are different in expected as follows

Input:

["column1", "column2", "date"]

Expected output:

["column3", "column4", "Date"]

How can I get the above output?

Answer:-

Inputs:-

a=['1', '2', '3', '4']

b= {"1"=>"10", "2"=>"20", "3"=>"30"}

Execute:

c=a.map{|i| b[i].nil?? i : b[i] }

Output:-

 ["10", "20", "30", "4"]

ray · Accepted Answer · 2019-02-22 13:23:17Z

1

You want to replace '_' with space or bring space when capital letter is encountered within string,

Try following rails methods to do so,

"now_isTheTime".titleize.camelize
 => "Now Is The Time"

answered Feb 22, 2019 at 13:23

ray

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Comments

shushugah · Accepted Answer · 2019-02-22 13:29:14Z

0

ar1 = [["date", "country_name", "month"], ["2019-02-21", "US", "Jan"]]
ar2 = ["name", "homeAddress", "zipcode"]


def formatter(string)
 return string if string.length < 3 || string.count("0-9").positive?

 string.titleize.camelize
end

ar1.map{ |sub_arr| sub_arr.map(&method(:formatter)) }
ar2.map(&method(:formatter))

answered Feb 22, 2019 at 13:29

shushugah

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