Run java executable from a groovy script on linux

Question

I know it's a bit strange but i'm trying to run the java executable from a groovy script:

def mycommand = "java -version"
def env = System.getenv().collect { k, v -> "$k=$v" }
def mycommandOut = mycommand.execute(env,null).text
println mycommandOut

this work well on windows but when I run it on Linux it seems to does nothing.

If i set mycommand = "ls -la" it works like a charm.

If i set mycommand = "foobar" i get: java.io.IOException: Cannot run program "foobar": error=2

Any hints?

Does it seem to do nothing or there's an error? What happens on the target Linux box when you execute that command in a shell? Is the java executable found? — marekful
– marekful, Commented Feb 26, 2019 at 14:36
It does nothing. I think java is found because if i set mycommand="foobar" i've go a java.io.IOException: Cannot run program "foobar" — sgargel
– sgargel, Commented Feb 26, 2019 at 14:41

cfrick · Accepted Answer · 2019-02-26 14:48:33Z

2

This is because java -version prints the info to STDERR on Linux. But you are capturing the STDOUT.

def proc = "java -version".execute()
proc.waitFor()
def version = proc.err.text

answered Feb 26, 2019 at 14:48

cfrick

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