How to filter a string in batch file?

Question

I want to handle the string such as project_Name_-_sofeware_Name.txt into project_Name.txt, so I wrote a script like following to run:

set temp1=%~n1
echo %temp1:-*=%

But the output of the bat still been project_Name_-_sofeware_Name.txt.

I have also written another bat file to get the folder name:

:GetFolderName
set temp2=%temp1%
set temp1=%temp2:*\=% 
If Not %temp1%==%temp2% Goto GetFolderName

And the output string is in line with expectations by far.

It also is weird. In my opinion, it should be FolderName after running temp1=%temp2:*\=%.

This is interesting. Where do you get the %temp1:-*=% construct from? Well, it does not work in Batch files... :/ — Aacini
– Aacini, Commented Feb 27, 2019 at 12:32
@GerhardBarnard: Are you suggesting to use a 1000-lines Batch-JScript hybrid script or an entirely different language to perform something that can be achieved in a very simple and short Batch line? I don't think it is a good advice... :( — Aacini
– Aacini, Commented Feb 27, 2019 at 12:48
for /F "tokens=2 delims=$" %%a in ("%temp1:_-_=$%") do echo %%a — Aacini
– Aacini, Commented Feb 27, 2019 at 12:56
@Aacini, misread the question, thought it was about replacing = :) — user7818749
– user7818749, Commented Feb 27, 2019 at 13:43
I'd never use string manipulation to get components of a path; rather I'd use the ~ modifiers of for loop variables... — aschipfl
– aschipfl, Commented Feb 27, 2019 at 16:01

Aacini · Accepted Answer · 2019-02-27 12:41:32Z

2

You may do that in a very simple way:

@echo off

set "temp1=project_Name_-_sofeware_Name.txt"

set "dummy=%temp1:_-_=" & set "temp2=%"

echo %temp2%

Further details at Split string with string as delimiter. Pay attention to the comment at such an answer...

answered Feb 27, 2019 at 12:41

Aacini

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