Sort rails hash based on array of items

Question

I have an array like this:

['one','three','two','four']

I have a array of hash like this:

[{'three' => {..some data here..} }, {'two' => {..some data here..} }, {:total => some_total }] # etc...

I want to sort the array of hashes by the first array. I know I can do:

array_of_hashes.sort_by{|k,v| k.to_s} to sort them and it will sort by the key

( and the .to_s to convert :total to a string )

How can I make this happen?

Edit:

I was incorrect about how this is setup, it is actually like this:

{'one' => {:total => 1, :some_other_value => 5}, 'two' => {:total => 2, :some_other_value => 3} }

If I need to put this in a new question, just let me know and I will do that.

Thank you

what Ruby version do you use?

fl00r
– fl00r

2011-03-30 19:49:52 +00:00
Commented Mar 30, 2011 at 19:49 — fl00r
– fl00r, Commented Mar 30, 2011 at 19:49

amitkaz · Accepted Answer · 2011-03-31 02:21:48Z

6

similar to ctcherry answer, but using sort_by.

sort_arr = ['one','three','two','four']
hash_arr = [{'three' => {..some data here..} }, {'two' => {..some data here..} }]

hash_arr.sort_by { |h| sort_arr.index(h.keys.first) }

answered Mar 31, 2011 at 2:21

amitkaz

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1 Comment

Toby Joiner Over a year ago

I got this to work with your solution with a modification: .sort_by{ |k,v| k = 'z' unless sort_list.include?(k); sort_list.index(k)}. I am sure there is a better way, but I don't know it. also I added 'z' to the sort_arr to give it a place stuff that wasn't found.

Chris Cherry · Accepted Answer · 2011-03-30 19:10:50Z

0

The index method of Array is your friend in this case:

sort_list = ['one','three','two','four']

data_list = [{'three' => { :test => 3 } }, {'two' => { :test => 2 } },  {'one' => { :test => 1 } },  {'four' => { :test => 4 } }]

puts data_list.sort { |a,b|
 sort_list.index(a.keys.first) <=> sort_list.index(b.keys.first)
}.inspect

Resulting in, the same order as the source array:

[{"one"=>{:test=>1}}, {"three"=>{:test=>3}}, {"two"=>{:test=>2}}, {"four"=>{:test=>4}}]

answered Mar 30, 2011 at 19:10

Chris Cherry

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