How to check if one array contains another in php in a sequence?

Question

I have two arrays:

$a = array("w","c","d","e","g","h");
$b = array("c","d","e");
$c = array("c","e","d");

It should return "TRUE" if we check if $a contain $b or $a contain $c because the index of $b are in sequence with $a & $c i.e.they all have $ "c","d","e" and they come in a sequence in $a. However, if $b = array("c", "g", "d"), then we should get false because it has all the elements but they are not in correct sequence in $a.

Tried anything?

Lawrence Cherone
– Lawrence Cherone

2019-02-28 22:34:40 +00:00
Commented Feb 28, 2019 at 22:34 — Lawrence Cherone
– Lawrence Cherone, Commented Feb 28, 2019 at 22:34

Miroslav Glamuzina · Accepted Answer · 2019-02-28 22:44:15Z

1

Something like this should do the trick:

$a = ["w","c","d","e","g","h"];
$b = ["c","d","e"];
$c = ["c","e","d"];
function containsSequence($arr, $subArray){
    $keys = array_keys($arr, $subArray[array_keys($subArray)[0]]); 
    foreach($keys as $k) {
        if(array_slice($arr, $k, count($subArray)) == $subArray){
            return true;    
        }
    }
    return false;
}
echo 'Contains sequence: '.(containsSequence($a,$b)?'yes:':'no');
echo 'Contains sequence: '.(containsSequence($a,$c)?'ues':'no');

answered Feb 28, 2019 at 22:44

Miroslav Glamuzina

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