Use object returned by Lua script

Question

I have this lua script inside "Conversion.lua" file:

local conversion = {}

function conversion.mmToin( value )
    return value * 0.0393701
end

return conversion

I need to use the function mmToin in C# code, contained inside the object conversion.

If the function would not be inside the object i would have use the following code:

Script scp = new Script();
scp.DoFile(GlobalConst.PATH_TO_SCRIPT_FOLDER + "Conversion.lua");
double resultFm = scp.Call(scp.Globals["mmToin"], 1).ToObject<double>();

but i can't use the function if i put it inside an object; i've tried:

double resultFm = scp.Call(scp.Globals["conversion.mmToin"], 1).ToObject<double>();

but is not working.

How can i use mmToin function inside C# code? Thanks.

You need to look up mmToin in the returned table, not in the global one. — tkausl
– tkausl, Commented Mar 4, 2019 at 11:40
Can you write the snippet that do that? I searched in the returned table DynValue.Table but the length is 0 — S.Orioli
– S.Orioli, Commented Mar 4, 2019 at 11:47
I don't really know how to do it in C# unfortunately, I'm used to using C to interact with Lua. However the Lua internals should work the same, so the DoFile should leave a table on the stack (the returnvalue) which has a key mmToin with the value of the function. — tkausl
– tkausl, Commented Mar 4, 2019 at 11:49
What do you mean by "is not working"? What exactly goes wrong? — canton7
– canton7, Commented Mar 4, 2019 at 11:52
Well exception is fired with message function is not a function and has no __call metamethod. I suppose because function is not found. — S.Orioli
– S.Orioli, Commented Mar 4, 2019 at 11:59

SirePi · Accepted Answer · 2019-03-04 11:58:37Z

1

You need to keep a reference to the returned value of your lua script as a DynValue object, then look for the desired function in the Table property.

DynValue dyn = scp.DoFile(GlobalConst.PATH_TO_SCRIPT_FOLDER + "Conversion.lua");

and you should be then able to call your function with

scp.Call(dyn.Table.Get("yourFunctionHere"), parameters).ToObject<double>();

answered Mar 4, 2019 at 11:58

SirePi

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