firebase.database() is not a function

Question

Error message:

TypeError: _this.db is not a function

Code:

import app from "firebase/app";
import "firebase/auth";
import "firebase/database";

const config = {
  apiKey: "some-api-key",
  authDomain: "myapp.firebaseapp.com",
  databaseURL: "https://myapp.firebaseio.com",
  projectId: "aofndiuf",
  storageBucket: "project-somenumber.appspot.com",
  messagingSenderId: "793813245724y6597"
};

class Firebase {
  constructor() {
    app.initializeApp(config);
    this.auth = app.auth();
    this.db = app.database();
  }
  //  Auth API

  doCreateNewsletter = (news, name, description, email) => {
    const newsletter = { news, name, description, email };
    const newPostKey = this.db()
      .ref()
      .child("newsletters")
      .push().key;
    return this.db
      .ref()
      .child("/newsletters/" + newPostKey)
      .set(newsletter);
  };

Doug Stevenson · Accepted Answer · 2019-03-04 23:55:16Z

1

You assigned this.db like this:

this.db = app.database();

But then you refer to it later like this:

const newPostKey = this.db()
    ...

The object returned from app.database() isn't a function, so you can't call it like a function as you are now. It's a Database object. Perhaps you can just get rid of those parenthesis to make your code work the way you intended.

answered Mar 4, 2019 at 23:55

Doug Stevenson

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3 Comments

Subhendu Kundu Over a year ago

He did const newPostKey = this.db() .ref() .child("newsletters") .push().key; there's a chaining. I guess that's not the issue.

Doug Stevenson Over a year ago

It's not the issue. The parenthesis after this.db that makes it a function call is the issue, as I explained.

Subhendu Kundu Over a year ago

Aha, that makes sense 😊

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