creating a object from array of strings

Question

My input is like

var resources = ["user-john","user-doe", "students-Milan"];

I am trying to get an output as an object like below,

{
  user: ["john", "doe"],
  students: ["Milan"]
}

What am i doing wrong

var resources = ["user-john","user-doe", "students-Milan"];

let tempObj = {}
resources.forEach(o => {
 let tempArr = o.split("-");
   if(tempObj[tempArr[0]]){
     tempObj[tempArr[0]] = [...tempArr[1], tempArr[1]]
   }else{
     tempObj[tempArr[0]] = [tempArr[1]]
  }
})

console.log(tempObj)

Nina Scholz · Accepted Answer · 2019-03-06 13:35:55Z

5

You could deconstructure the splitted string and build an array as value.

var resources = ["user-john", "user-doe", "students-Milan"],
    result = resources.reduce(
        (r, s) =>
            ((key, value) => Object.assign(r, { [key]: [].concat(r[key] || [], value) }))
            (...s.split('-')),
        {}
    );
  
console.log(result);

edited Mar 6, 2019 at 13:35

answered Mar 6, 2019 at 13:29

Nina Scholz

388k26 gold badges367 silver badges417 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Nenad Vracar · Accepted Answer · 2019-03-06 13:24:48Z

3

You could use reduce method here with an object as a accumulator value.

var data = ["user-john", "user-doe", "students-Milan"];
var result = data.reduce((r, e) => {
  let [key, value] = e.split('-');
  r[key] = (r[key] || []).concat(value)
  return r;
}, {})

console.log(result)

answered Mar 6, 2019 at 13:24

Nenad Vracar

122k16 gold badges160 silver badges184 bronze badges

Comments

James Coyle · Accepted Answer · 2019-03-06 13:29:32Z

3

A clean, modern solution:

var resources = ["user-john","user-doe", "students-Milan"];

const output = {}

resources.forEach(item => {
  const [key, value] = item.split('-')      
  output[key] = [...output[key] || [], value]
})

console.log(output)

answered Mar 6, 2019 at 13:29

James Coyle

10.5k2 gold badges42 silver badges49 bronze badges

Comments

binariedMe · Accepted Answer · 2019-03-06 13:23:43Z

2

Here in this part you actually need to :

resources.forEach(o => {
  let tempArr = o.split("-");
  if(tempObj[tempArr[0]]){
    tempObj[tempArr[0]] = [...tempObj[tempArr[0]], tempArr[1]];
  }else{
  tempObj[tempArr[0]] = [tempArr[1]]
  }
})

answered Mar 6, 2019 at 13:23

binariedMe

4,3291 gold badge20 silver badges34 bronze badges

Comments

Atul Sharma · Accepted Answer · 2019-03-06 13:27:20Z

2

var resources = ["user-john","user-doe", "students-Milan"];
var tmp = {};
resources.forEach(function(e){
	var a = e.split("-");
	if(typeof tmp[a[0]] == "undefined"){
		tmp[a[0]] = [];
		tmp[a[0]].push(a[1]);
	}else{
		tmp[a[0]].push(a[1]);
	}
});
console.log(tmp);

answered Mar 6, 2019 at 13:27

Atul Sharma

11k10 gold badges42 silver badges69 bronze badges

Comments

R3tep · Accepted Answer · 2019-03-06 13:24:02Z

1

You can use .push method instead [...tempArr[1], tempArr[1]]

var resources = ["user-john","user-doe", "students-Milan"];

let tempObj = {}
resources.forEach(o => {
 let tempArr = o.split("-");
   if(tempObj[tempArr[0]]){
     tempObj[tempArr[0]].push(tempArr[1])
   }else{
     tempObj[tempArr[0]] = [tempArr[1]]
  }
})

console.log(tempObj)

Or you can use the spread syntax on the last state of your array like [...tempObj[tempArr[0]], tempArr[1]] instead [...tempArr[1], tempArr[1]]

answered Mar 6, 2019 at 13:24

R3tep

12.9k10 gold badges52 silver badges77 bronze badges

Collectives™ on Stack Overflow

creating a object from array of strings

6 Answers 6

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related