One Line Command in Linux Bash

Question

I am trying to write a basic one line Linux Bash command, which gives all the numbers between 1 - 1000 as an input to an exe program.

the exe program looks like this:

please insert 1:   1(wanted input)
please insert 2:   2(wanted input)
.
.
.
.
please insert 1000:  1000(wanted input)
success!

so I have tried writing this linux bash command:

for((i=1;i<=1000;i+=1)); do echo "$i"|./the_exe_file; done

but the problem is that my command OPENS the exe file on each iterate of the for... which means, only the first input (1) is right. And, for some reason, the input that is given to the exe file seems not to be good. what can I do? Where is my mistake?

Thanks in advance.

Poshi · Accepted Answer · 2019-03-08 11:50:23Z

1

You asked the exe to be opened in every loop iteration. It you only need it to be opened a single time, take it out of the loop:

for((i=1;i<=1000;i+=1)); do echo "$i"; done | ./the_exe_file

answered Mar 8, 2019 at 11:50

Poshi

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1 Comment

Poshi Over a year ago

If it worked and solved your problem, it would be good that you mark the answer as accepted :-)

Paul Hodges · Accepted Answer · 2019-03-08 14:50:15Z

1

Likewise, you might find it more readable to use the tool designed for this.

seq 1 1000 | ./the_exe_file

answered Mar 8, 2019 at 14:50

Paul Hodges

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2 Comments

chepner Over a year ago

Strictly speaking, seq may not be installed on the current machine, while bash is guaranteed to be available on a machine running a bash script.

Paul Hodges Over a year ago

True. If it's there, I'd use it. If not, I'd use a loop rather than bothering to install it. :)

pjh · Accepted Answer · 2019-03-08 18:50:11Z

1

Try

printf '%s\n' {1..1000} | ./the_exe_file

answered Mar 8, 2019 at 18:50

pjh

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Comments

dr-who · Accepted Answer · 2019-06-29 03:31:39Z

0

In bash:

$ for f in {1..1000}; do echo $f; done

to test:

$ for f in {1..1000}; do echo $f; done  | uniq | wc -l
1000

answered Jun 29, 2019 at 3:31

dr-who

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