Export functions individually in NodeJS

Question

Sorry if it's a duplicate but I can't find the solution to this issue.

In NodeJS, I need to export functions from one file to another. Here is what I tried in order to export (written in typescript):

/*** db.ts ***/

module.exports = {
    getDoc: (id:string):any =>  {
        return new Observable((observer:any) => {
            //Do something
        });
    },
    addDoc: (document:any):any =>  {
        return new Observable((observer:any) => {
            //Do something
        });
    },
}

And to import:

/*** main.ts ***/

import { getDoc, addDoc } from './db'

I want to keep this structure (being able to call each function - getDoc and addDoc - separately).

What am I doing wrong? The export doesn't seem to work.

What is value of 'module' in tsconfig.json

Amit
– Amit

2019-03-11 11:10:07 +00:00
Commented Mar 11, 2019 at 11:10 — Amit
– Amit, Commented Mar 11, 2019 at 11:10

Estus Flask · Accepted Answer · 2019-03-11 11:13:15Z

2

CommonJS exports aren't type-safe.

If they are used as named imports:

import { getDoc, addDoc } from './db'

They should be named exports as well:

export const getDoc = (id:string):any =>  {
    return new Observable((observer:any) => {
        //Do something
    });
};

export const addDoc = (document:any):any =>  {
    return new Observable((observer:any) => {
        //Do something
    });
};

Both export and import are supposed to be transpiled to CommonJS modules by TypeScript.

answered Mar 11, 2019 at 11:13

Estus Flask

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Comments

Ritviz Sharma · Accepted Answer · 2019-03-11 11:03:35Z

0

You can do like this:

module.exports = {
    firstMethod: function() {},
    secondMethod: function() {}
}

For calling your methods

var Methods = require('./db.js');
var method = Methods.firstMethod;

answered Mar 11, 2019 at 11:03

Ritviz Sharma

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