replace empty list with values in another column in pandas dataframe

Question

I am trying to replace list of values in one column with another column, below is data and script I am using

old = [[51, 1], 
          [52, 1], 
          [53, -1], 
          [], 
          [54, 0], 
          [55, 0], 
          [52, 0], 
          [], 
          [52, 0], 
          [54, -1]]

import pandas as pd
df = pd.DataFrame(columns=['old','new'])     
df["old"]=old

new = [[51, 1], 
          [52, 1], 
          [53, -1], 
          [54, -2], 
          [54, 0], 
          [55, 0], 
          [52, 0], 
          [55. -3], 
          [52, 0], 
          [54, -1]]

df["new"]=new

for index, row in df.iterrows():
    if ((df["old"][index])==[]) :
        df.old[index] = df.new[index]

Is there any better way than using for loop , actually in my script there are too many loops so i want to avoid using for loop for few data manipulation If anyone knows that will be great help

cs95 · Accepted Answer · 2019-03-11 15:11:07Z

3

You can use Series.mask:

# df['old'] = df['old'].mask(df['old'].str.len() == 0, df['new'])
df['old'].mask(df['old'].str.len() == 0, df['new'])

0     [51, 1]
1     [52, 1]
2    [53, -1]
3    [54, -2]
4     [54, 0]
5     [55, 0]
6     [52, 0]
7      [52.0]
8     [52, 0]
9    [54, -1]
Name: old, dtype: object

edited Mar 11, 2019 at 15:11

answered Mar 11, 2019 at 14:55

cs95

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