Adding position/order in array of objects

Question

I have an array of objects like below:

    [{
    "id": 1,
    "Size": 90,
    "Maturity": 24,
   },
  {
    "id": 2,
    "Size": 85,
    "Maturity": 22,
  },
  {
    "id": 3,
    "Size": 80,
    "Maturity": 20,
   }]

I need to this Array on basis of different property value sorting (eg: Maturity) and also add a column order which has the ascending order/rank. Eg:

      [{
        "id": 1,
        "Size": 90,
        "Maturity": 22,
         "Order": 2
       },
      {
        "id": 2,
        "Size": 85,
        "Maturity": 25,
        "Order": 3
      },
      {
        "id": 3,
        "Size": 80,
        "Maturity": 20,
        "Order": 1
       }]

In which language will you do that? By the way, your sample order numbering is not accurate, am I wrong? — vahdet
– vahdet, Commented Mar 13, 2019 at 12:40
The two examples have different data so it is hard to understand what you are asking. Also, you should post your code, so we can see what you tried. — Technotronic
– Technotronic, Commented Mar 13, 2019 at 12:57

Technotronic · Accepted Answer · 2019-03-13 12:56:40Z

1

const arr = [{
    "id": 1,
    "Size": 90,
    "Maturity": 24,
   },
   {
    "id": 2,
    "Size": 85,
    "Maturity": 22,
   },
   {
    "id": 3,
    "Size": 80,
    "Maturity": 20,
   }];

arr
  .map((item,index) => ({ ...item, Order: index + 1 }))
  .sort((a, b) => b.Maturity - a.Maturity)

answered Mar 13, 2019 at 12:56

Technotronic

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Comments

vahdet · Accepted Answer · 2019-03-13 13:01:09Z

0

Sort the array with sort and then add prop to each object with respect to the index they are sorted on with forEach:

var inp = [{
    id: 1,
    Size: 90,
    Maturity: 24,
   },
  {
    id: 2,
    Size: 85,
    Maturity: 22,
  },
  {
    id: 3,
    Size: 80,
    Maturity: 20,
   }]
   
// Sort
inp.sort(function(a, b){
  return a.Maturity == b.Maturity ? 0 : +(a.Maturity > b.Maturity) || -1;
});

// add prop
inp.forEach(function(row, index) {
  row.index = index + 1;
});

console.log(inp)

answered Mar 13, 2019 at 13:01

vahdet

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Comments

user10704605 · Accepted Answer · 2019-03-13 13:02:54Z

0

var objs = [ 
    {
    "id": 1,
    "Size": 90,
    "Maturity": 24,
   },
  {
    "id": 2,
    "Size": 85,
    "Maturity": 22,
  },
  {
    "id": 3,
    "Size": 80,
    "Maturity": 20,
   }];
function compare(a,b) {
  if (a.Size < b.Size)
    return -1;
  if (a.Size > b.Size)
    return 1;
  return 0;
}

objs.sort(compare);
for (var i = 0; i < objs.length; i++) {
    objs[i].Order = i+1;
}
console.log(objs);

answered Mar 13, 2019 at 13:02

user10704605

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