Geting version of python executable from a script

Question

I have different python versions installed (from source) on my server. Now I'd like to be able to get the version of a python executable from another python script (running another python version).

I know I can do it from the shell with path/to/python -V. But I'd like to do it from a script, like:

command = ' '.join([pythonpath, '-V'])
output = subprocess.check_output( command, shell=True )
print output

But in this case check_output does not work as expected: the output is shown in the terminal but does not go into the variable output.

@Aran-Fey Since it is a variable, I belive it must be the path to one of his Python commands — Siddharth Dushantha
– Siddharth Dushantha, Commented Mar 13, 2019 at 20:09
In the meantime I found a workaround here: linuxconfig.org/check-python-version. So the command is /path/to/python /path/to/check_python_script.py. With this command check_output works as expected. — Georg Pfolz
– Georg Pfolz, Commented Mar 13, 2019 at 20:12

Dmitrii · Accepted Answer · 2020-01-03 02:17:49Z

1

Code:

#!/usr/bin/python2
# -*- coding: utf-8 -*-

from subprocess import Popen, PIPE

if __name__ == '__main__':

    cmd = '/usr/local/bin/python2'
    param = '-V'

    process = Popen([cmd, param], stdout=PIPE, stderr=PIPE)
    process.wait()

    # be aware, the order should be out, err for shell tools, but python reply shows in err, out, i've no idea why

    err, out = process.communicate()

    print out

Output:

Python 2.7.15

You can see source code here.

edited Jan 3, 2020 at 2:17

answered Mar 13, 2019 at 20:17

Dmitrii

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1 Comment

Georg Pfolz Over a year ago

It doesn't work for me, same problem as with my own initial script: the result of out = process.communicate()[0].splitlines() is printed but the variable out is an empty list. Maybe it works on Python 3, I'm working on 2.7.15.

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