JS find multiple values in array [duplicate]

Question

I have an array which the values are :

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26

then i want to check this values to the array :

14,15,16,17

i tried with this but didn't work :

function contains(a, toFind) {
    for (var i = 0; i < a.length; i++) {
        if (equalArray(a[i], toFind)) {
            return true;
        }
    }
    return false;
}

function equalArray(a, b) {
    if (a.length === b.length) {
        for (var i = 0; i < a.length; i++) {
            if (a[i] !== b[i]) {
                return false;
            }
        }
        return true;
    } else {
        return false;
    }
}

Anyone can help me out ?

The code you are using would only work if both were arrays of arrays. — Luca Kiebel
– Luca Kiebel, Commented Mar 14, 2019 at 11:10
What does "then i want to check this values to the array" mean? You want to see if it has any of them? All of them? In that order? In any order? Consecutively? — T.J. Crowder
– T.J. Crowder, Commented Mar 14, 2019 at 11:10
SOLVED https://stackoverflow.com/questions/9204283/how-to-check-whether-multiple-values-exist-within-an-javascript-array — 0x00b0
– 0x00b0, Commented Mar 14, 2019 at 11:11

Stanimirovv · Accepted Answer · 2019-03-14 11:12:07Z

0

use includes.

let a = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26];

console.log(a.includes(14));
console.log(a.includes(15));
console.log(a.includes(16));
console.log(a.includes(17));

answered Mar 14, 2019 at 11:12

Stanimirovv

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