How to attach an xml file to php variable

Question

i have been created an xml file and named it 'input.xml'. When i'm trying to add a file (attach to string) in php, i get 500 browser error.

This is how i importing my xml to variable (working way):

 $xmlstr = <<<XML
<?xml version='1.0' standalone='yes'?>
<movies>
 <movie>
  <title>Movie 1</title>
 </movie>

  <movie>
  <title>Movie 2</title>
 </movie>

 <categories>
  <category>
    <name>Example category</name>
  </category>
 </categories>
</movies>
XML;

This is how i want to import my xml (from input.xml file) (not working way):

 $xmlstr = simplexml_load_file("input.xml");

This is how my php code looks like:

$movies = new SimpleXMLElement($xmlstr);

foreach ($movies->movie as $mov) {
   echo "We found a movie!<br>";
}

foreach ($movies->categories as $cat) {
    echo "We found a category!<br>";
}

And this is my input.xml file content:

<?xml version='1.0' standalone='yes'?>
<movies>
 <movie>
  <title>Movie 1</title>
 </movie>

  <movie>
  <title>Movie 2</title>
 </movie>

 <categories>
  <category>
    <name>Example category</name>
  </category>
 </categories>
</movies>

try $movies = simplexml_load_file("input.xml"); as simplexml_load_file returns an SimpleXMLElement Object — Sindhara
– Sindhara, Commented Mar 16, 2019 at 17:47
Hello @gview, Im getting this error: Backend fatal error: PHP Fatal error: Uncaught Exception: String could not be parsed as XML in ..../zil/index.php:21\nStack trace:\n#0 ....}/zil/index.php(21): SimpleXMLElement->__construct('')\n#1 {main}\n thrown in ..../zil/index.php on line 21\n My 21 line: $movies = new SimpleXMLElement($xmlstr); — Adrijus Jakučionis
– Adrijus Jakučionis, Commented Mar 16, 2019 at 17:49
If you don't pass true as the third argument (data_is_url) in the constructor for new SimpleXMLElement(), it will use the first argument as XML-data, not as a path. So you must do: new SimpleXMLElement('input.xml', 0, true). You should always refer to the manual if you can't get a PHP function/object working as expected. — M. Eriksson
– M. Eriksson, Commented Mar 16, 2019 at 17:51

u_mulder · Accepted Answer · 2019-03-16 17:48:50Z

3

simplexml_load_file already returns a SimpleXMLElement for you. So, there's no need to use

$movies = new SimpleXMLElement($xmlstr);

Just:

$movies = simplexml_load_file("input.xml");

foreach ($movies->movie as $mov) {
   echo "We found a movie!<br>";
}

foreach ($movies->categories as $cat) {
    echo "We found a category!<br>";
}

answered Mar 16, 2019 at 17:48

u_mulder

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u_mulder Over a year ago

Feel free to accept an answer if it helps. Also if your other questions have a solution - accept ot/them too.

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