Mutiline String from array

Question

I have to create a string formate for creating bills.I have an array contains dictionaries.I tried but not able to create string like this. Structure of array is like this.

[["orderid": 139, "productfullqty": 1, "productprice": 8.0, "productname": Falafel, "id": 544, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  12, "productprice":  5.4, "productname":  Tomato, "id": 545, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  18, "productprice":  180.0, "productname":  Green Sauce, "id": 546, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  1, "productprice":  0.46, "productname":  Onions, "id": 547, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  1, "productprice":  8.0, "productname":  Falafel, "id": 548, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  12, "productprice":  5.4, "productname":  Tomato, "id": 549, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  18, "productprice":  180.0, "productname":  Green Sauce, "id": 550, "producthalfqty": , "productonfourthqty": , "productthirdqty": ], ["orderid": 139, "productfullqty":  1, "productprice":  0.46, "productname":  Onions, "id": 551, "producthalfqty": , "productonfourthqty": , "productthirdqty": ]]

Using this array, I have to create string like this.

Thanks in advance.

Why not convert this collection to array of objects? It would be cleaner to operate. Once you done that append a new line with your data and spacing format value through a for loop or map function and later with that string array you can also use joined() function for collections by passing "\n" new line as a separator. — Amber K
– Amber K, Commented Mar 18, 2019 at 7:18
Do you want to have the same alignment? Because it will work only if the font used to print it later is monospace. What have you tried? — Larme
– Larme, Commented Mar 18, 2019 at 9:07
@Larme , Thanks for response , We need to print customer order bill via star micronics printer. And i got one demo from star micronics support , in that this type of demo bill format is given. So , we are considering this format to print bill. — Amit gupta
– Amit gupta, Commented Mar 18, 2019 at 10:05
As a first step, you need to get rid of the array of dictionaries and create a struct that represents each line item. This will dramatically simplify your code. — Rob Napier
– Rob Napier, Commented Mar 18, 2019 at 12:49

Vladimir Konon · Accepted Answer · 2019-03-18 10:53:05Z

You could try this.

let Falafel = "Falafel"
let Tomato = "Tomato"
let GreenSauce = "Green Sauce"
let Onions = "Onions"

let orders = [["orderid": 139, "productfullqty": 1, "productprice": 8.0, "productname": Falafel, "id": 544, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1], ["orderid": 139, "productfullqty":  12, "productprice":  5.4, "productname":  Tomato, "id": 545, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1], ["orderid": 139, "productfullqty":  18, "productprice":  180.0, "productname":  GreenSauce, "id": 546, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1], ["orderid": 139, "productfullqty":  1, "productprice":  0.46, "productname":  Onions, "id": 547, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1], ["orderid": 139, "productfullqty":  1, "productprice":  8.0, "productname":  Falafel, "id": 548, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty":1 ], ["orderid": 139, "productfullqty":  12, "productprice":  5.4, "productname":  Tomato, "id": 549, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1], ["orderid": 139, "productfullqty":  18, "productprice":  180.0, "productname":  GreenSauce, "id": 550, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1], ["orderid": 139, "productfullqty":  1, "productprice":  0.46, "productname":  Onions, "id": 551, "producthalfqty": 1, "productonfourthqty": 1, "productthirdqty": 1]]

var result = "SKU            Description                        Total\n"
var subTotal: Decimal = 0
orders.forEach { (order) in
    if let sku = order["id"],
        let name = order["productname"],
        let value = order["productprice"],
        let price = value as? NSNumber
    {
        let SKU = "\(sku)".cString(using: .utf8)!
        let NAME = "\(name)".cString(using: .utf8)!
        let PRICE = String(format:"%0.2f", price.doubleValue).cString(using: .utf8)!
        let string = String(format: "%-15s%-32s%8s\n", OpaquePointer(SKU), OpaquePointer(NAME), OpaquePointer(PRICE))
        result.append(string)
        subTotal += price.decimalValue
    }
}
result.append("Subtotal                                         \(subTotal)\n")
result.append("Tax                                                 \(0.00)\n")

print("\(result)")

Just fixed your data structure. Look at: " "producthalfqty": , "productonfourthqty": , "productthirdqty": ] " You should put some values or do not add these keys

Amber K · Accepted Answer · 2019-03-18 07:33:16Z

0

struct MyOrder {
let id: Int
let orderId: Int
let fullQuantity: Int
let halfQuantity: Int
let quarterQuantity: Int
let price: Double
let name: String

init?(dict: [String:Any]) {
    guard let id = dict["id"] as? Int,
        let name = dict["productname"] as? String
    //..
    //..
    // so on
    else { return nil }
    self.id = id
    self.name = name
}
}

let dataArray = [["id":0,"productname":"Oreo"]]
    let orders = dataArray.compactMap { MyOrder(dict: $0) }
    let myStringRows = orders.map{ "\($0.id)\t\t\($0.name)\t\t" } // format your data here.
    let myFinalTable = myStringRows.joined(separator: "\n")
    print(myFinalTable)

answered Mar 18, 2019 at 7:33

Amber K

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Comments

andrew.turkin · Accepted Answer · 2019-03-18 10:52:25Z

0

First, ensure that your JSON is valid

Second, you can decode your JSON as an array of dictionary with:

let order = try? JSONDecoder().decode([[String:Any]], from: #JSONString)

answered Mar 18, 2019 at 10:52

andrew.turkin

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