lambda function returning function name

Question

I have a list where the items are dictionaries. the dictionary values are in unicode format and am trying to compare the unicode values to strings. So, I tried a below lambda function expecting a conversion of unicode to string;

a=[(lambda x: x.unicode('UTF-8') ) for i in paid_submissions[0].values()]

print(a)

[ at 0x11335db18>, at 0x113357d70>, at 0x113357b90>, at 0x113357a28>, at 0x1133b5050>, at 0x1133b50c8>]

FHTMitchell · Accepted Answer · 2019-03-18 14:57:13Z

3

Because you're just returning the lambda object without calling it on anything. If I understand what you're trying to do correctly, you would need to call the lambda on i like so.

a = [(lambda x: x.unicode('UTF-8'))(i) for i in paid_submissions[0].values()]

But the lambda expression is a waste. This can be more easily (and more efficiently) written as

a = [i.unicode('UTF-8') for i in paid_submissions[0].values()]

answered Mar 18, 2019 at 14:57

FHTMitchell

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2 Comments

Thirai Over a year ago

Thanks , the second syntax without lambda works! However the first syntax with lambda throws an error like; TypeError: <lambda>() takes exactly 1 argument (0 given)

FHTMitchell Over a year ago

@Thirai I had forgotten to pass the i in the first one but it should be fixed now. You shouldn't use it anyway -- hence why I'm not used to writing it :)

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