PHP passing argument to a function inside preg_replace

Question

Hi I have something like this:

$content = preg_replace('#(\s*)\<pre(.*?)\>(.*?)\</pre\>(\s*)#sie', 'dostuff(\'\\3\', \'\\2\', $content, \'\', \'\\1\', \'\\4\');', $content);

and

$content = preg_replace('#(\s*)\<code(.*?)\>(.*?)\</code\>(\s*)#sie', 'dostuff(\'\\3\', \'\\2\', $content, \'\', \'\\1\', \'\\4\');', $content);

How can I pass a true/false argument to the dostuff function inside, depending on the element that's being regexed? If it's <pre> to be true, and if it's <code> to be false?

Your code. As a rule of thumb: Never use the e-modifier or eval. There are exceptions, but they are rare. Right now I could do a simple <code>', eval(My code goes here), '</code> and would have a nice arbitrary-code-execution console for your site ;) — NikiC
– NikiC, Commented Apr 2, 2011 at 10:00
I have a excuse: I didn't write it :) I'm trying to create a simple syntax highlighter for my site and this is what I found trough google so far — Alex
– Alex, Commented Apr 2, 2011 at 10:04
Why not to use preg_match_all() to get all metches and than working with result? — Achilleterzo
– Achilleterzo, Commented Apr 2, 2011 at 10:22

duri · Accepted Answer · 2011-04-02 10:10:44Z

1

Why don't you use (pre|code) in your regexp? You would be able to use $n or \n reference to name of the HTML tag and use it as a dostuff()'s argument.

answered Apr 2, 2011 at 10:10

duri

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