How to add new rows and columns to pad numpy array

Question

I have an array of matrices all of different sizes/dimensions and I need to pad them all to the same size (805, 16866). Bellow is the code I'm currently using to do this but I believe it could be vectorised, however I am not sure how to do this.

x1 = np.zeros((805, 16866))

for i in range(x[0].shape[0]):
    for j in range(x[0].shape[1]):
        x1[i, j] = x[0][i, j]

You can use np.pad.

javidcf
– javidcf

2019-03-18 17:59:27 +00:00
Commented Mar 18, 2019 at 17:59 — javidcf
– javidcf, Commented Mar 18, 2019 at 17:59

Mister Brainley · Accepted Answer · 2019-03-18 17:47:57Z

2

In the above example, x1[:x[0].shape[0], :x[0].shape[1]] = x should work

answered Mar 18, 2019 at 17:47

Mister Brainley

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Comments

pittix · Accepted Answer · 2019-03-18 17:53:53Z

0

There's the numpy.pad function (docs) which does what you need.

The code you want is

x1 = np.zeros((805,16866))

for i in range(x.shape[0])
  x1[i,:]= np.pad(x[i,:],x1.shape[0],'constant',constant_values=0)

answered Mar 18, 2019 at 17:53

pittix

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