Using subprocess.call to execute python file?

Question

I am using subprocess.call in order to execute another python file. Considering that the script that will be called will never terminate the execution as it's inside an infinite loop, how can I make it possible for the original script to continue the execution after the subprocess call ?

Example: I have script1.py which does some calculations and then calls script2.py using subprocess.call(["python", "script2.py"]), since it's inside an infinite loop the script1 gets stuck on execution, is there another way to run the file other than using subprocess module ?

Can you just shove the response in a future or on a second thread or something like that and forget about it? — Trevor K
– Trevor K, Commented Mar 18, 2019 at 21:10
There is no need to use subprocess for this. Have script1.py import script2 and call its main function. — BoarGules
– BoarGules, Commented Mar 18, 2019 at 21:18

zvone · Accepted Answer · 2019-03-18 21:10:47Z

2

subprocess.call(["python", "script2.py"]) waits for the sub-process to finish.

Just use Popen instead:

proc = subprocess.Popen(["python", "script2.py"])

You can later do proc.poll() to see whether it is finished or not, or proc.wait() to wait for it to finish (as call does), or just forget about it and do other things instead.

BTW, you might want to ensure that the same python is called, and that the OS can find it, by using sys.executable instead of just "python":

subprocess.Popen([sys.executable, "script2.py"])

answered Mar 18, 2019 at 21:10

zvone

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