Javascript return array from array of objects where property value matches

Question

Is there a built in Javascript function or library to do the following:

const data = [
    { name: 'name1', type: 'type1' },
    { name: 'name2', type: 'type2' },
    { name: 'name3', type: 'type3' },
    { name: 'name4', type: 'type2' },
];

To search the following and return all objects where type = 'type2'

Something similar to data.findIndex((i) => i.type === 'type2') but returns all matches rather than first index?

Thanks

Possible duplicate of Javascript: How to filter object array based on attributes? — Jibin Joseph
– Jibin Joseph, Commented Mar 22, 2019 at 16:53

Ori Drori · Accepted Answer · 2019-03-22 16:50:11Z

9

You are looking for Array.filter():

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

Example:

const data = [
    { name: 'name1', type: 'type1' },
    { name: 'name2', type: 'type2' },
    { name: 'name3', type: 'type3' },
    { name: 'name4', type: 'type2' },
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

answered Mar 22, 2019 at 16:50

Ori Drori

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Comments

Maheer Ali · Accepted Answer · 2019-03-22 16:50:58Z

1

You can use filter()

const data = [
    { name: 'name1', type: 'type1' },
    { name: 'name2', type: 'type2' },
    { name: 'name3', type: 'type3' },
    { name: 'name4', type: 'type2' },
];
let res = data.filter(({type}) => type === "type2");
console.log(res)

answered Mar 22, 2019 at 16:50

Maheer Ali

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