is there a command to know if an array has their keys as string or plain int?
Like:
$array1 = array('value1','value2','value3');
checkArr($array1); //> Returns true because there aren't keys as string
And:
$array2 = array('key1'=>'value1','key2'=>'value2','value3');
checkArr($array2); //> Returns false because there are keys as string
Note: I know I can parse all the array to check it.
The "compact" version to test this is:
$allnumeric =
array_sum(array_map("is_numeric", array_keys($array))) == count($array);
@Gumbo's suggestion is 1 letter shorter and could very well be a bit speedier for huge arrays:
count(array_filter(array_keys($array), "is_numeric")) == count($array);
If you want to check the array's keys, it would be probably better to use something like this:
reset($array);
while (($key = key($array)) !== null) {
// check the key, for example:
if (is_string($key)) {
// ...
}
next($array);
}
This will be most performant, as there are no extraneous copies made of variables that you are not going to use.
On the other hand, this way is probably the most readable and makes the intent crystal clear:
$keys = array_keys($array);
foreach($keys as $key) {
// check the key, for example:
if (is_string($key)) {
// ...
}
}
Take your pick.
Important note:
Last time I checked, PHP would not let you have keys which are string representations of integers. For example:
$array = array();
$array["5"] = "foo";
echo $array[5]; // You might think this will not work, but it will
So keep that in mind when you are checking what the types of such keys are: they might have been created as strings, but PHP will have converted them to integers behind the scenes.
