PHP: How to set the value of a variable through another variable?

Question

I have a variable that calls an item, but what I have to display is the description of his category. So the structure I figured out is something like this willing that writing $item1 in $var1 it displays "Bla Bla Bla" (the value of $cat1):

$var1 = $item1;
$item1 = $cat1;
$cat1 = 'Bla Bla Bla';

Believe or not it doesn't work :-) I am a novice with php, sorry to ask stupid questions! And thank you so much to help!

are you maybe trying something like $var1->cat1 ? just guessing here — jonathan Heindl
– jonathan Heindl, Commented Mar 28, 2019 at 22:13
Yes and my english does not help (I am Italian)... indeed I would like to write <?php echo $var1; ?> in my page and display "Bla Bla Bla" but I need to use those 3 variables — Foorio
– Foorio, Commented Mar 28, 2019 at 22:14
Because it is the product, the category and the family... so when I set the product I need also to display the Family Description — Foorio
– Foorio, Commented Mar 28, 2019 at 22:16

Alireza Zojaji · Accepted Answer · 2019-03-29 02:00:22Z

4

assignation of values in most common programm languajes is up to down (cascade programming style)

$var1 = $item1;  <--- at this point $item1 is "empty" or null
$item1 = $cat1;  <--- at this point $cat1 is empty too
$cat1 = 'Bla Bla Bla';  <--- here $cat1 take value 'Bla Bla Bla'

so, you have to invert order of assignation like this:

$cat1 = 'Bla Bla Bla';
$item1 = $cat1;
$var1 = $item1;

the output show 'Bla Bla Bla' for $cat1 $item1 and $var1 hope this help.

edited Mar 29, 2019 at 2:00

Alireza Zojaji

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answered Mar 28, 2019 at 22:24

Sebastian P.

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