Loop Multidimensional PHP arrays and display all the corresponding array

Question

I've found an almost similar problem on this topic Loop Multidimensional PHP arrays My array is a little different but almost similar:

Array  
    (   
        [size] => int (995)
        [data] => Array
            (
                [0] => Array
                    (
                        [service] => 8000
                        [network] => xxx.xxx.xxx
                    )
            
                [1] => Array
                    (
                        [service] => 9000
                        [network] => xxx.xxx.xxx
                    )
                [2] => Array
                    (
                        [service] => 9500
                        [network] => xxx.xxx.xxx
                    )
            )    
    )

I d like to check all the service values in order to see if the number entered by the user is valid and exists, and display the corresponding network

Here is my naïve try:

$record = NULL;

// let's assume $x as this array here
foreach($record in $x['data']){
    if($record['service'] == $bus){
        break;
    }
}

if($record){
    // record found
    var_dump($record);
}else{
    echo "Not found";
}

Before using foreach loop, you should check the doc php.net/manual/en/control-structures.foreach.php — Nik
– Nik, Commented Apr 1, 2019 at 20:45
Thanks a lot Nick. I just Don't understand why in the link I posted, he needs tto use 3 imbricated foreach loop and I need to use only one ? — john_johnk
– john_johnk, Commented Apr 1, 2019 at 21:19
In the question you posted the user wanted to print all the items, subitems and subsubitems. In your case you need to iterate over only one level $x['data'] and print an item if it fits. — Nik
– Nik, Commented Apr 1, 2019 at 21:24
Of course not but I don't understand why I had a negative vote on my post. I really took time to write it most clear as possible — john_johnk
– john_johnk, Commented Apr 4, 2019 at 8:01

AbraCadaver · Accepted Answer · 2019-04-01 20:53:16Z

1

Just for fun, assuming that service is unique:

$services = array_column($x['data'], null, 'service');

if(isset($services[$bus]) {
    echo $services[$bus]['network'];
} else {
    echo "Not found";
}

Extract an array and index it by service
Now you can access it by $services[$bus] ex. $services[8000]['network'].

answered Apr 1, 2019 at 20:53

AbraCadaver

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Comments

jonathan Heindl · Accepted Answer · 2019-04-01 21:56:02Z

0

almost right :

forEach syntax is the other way round : forEach(<array> as $iterator) oh an you need to handle the assignment to the $reslt variable (which I renamed to $found for some reason ) a bit different

 $found=NULL;
    // let's assume $x as this array here
    foreach($x['data'] as $record ){
        if($record['service'] == $bus){
            $found=$record['service'];
        }
    }

    if($found != NULL){
        // record found
        var_dump($record);
    }else{
        echo "Not found";
    }

edited Apr 1, 2019 at 21:56

answered Apr 1, 2019 at 20:46

jonathan Heindl

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3 Comments

joka00 Over a year ago

Please add here some description of what have you changed in the code or where the mistake was.

Markafa Creative Solutions Over a year ago

He changed the statement "in" to "as" in the foreach parameters, and added a var_dump($record); line in the if statement bellow.

joka00 Over a year ago

Ok, but still please add some description to the post remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

Michael Peng · Accepted Answer · 2019-04-01 22:39:32Z

0

Adding onto Johnathon Heindl:(sorry i cannot reply yet).

It may be useful to make $found an array, in case you found the same service having different networks.

$found=[];
// let's assume $x as this array here
foreach($x['data'] as $record ){
   if($record['service'] == $bus){
       //appends to $found
       $found[]=$record['service'];
   }
}
if(!empty($found){
   // record(s) found
   var_dump($record);
}else{
   echo "Not found";
}

edited Apr 1, 2019 at 22:39

answered Apr 1, 2019 at 22:19

Michael Peng

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Comments

bad_coder · Accepted Answer · 2021-04-28 04:19:18Z

0

If I'm getting your question right, it should be something like this:

// For the sake of the example, first I reconstructed your array:
$ar1 = array("service" => 8000, "network" => "111.111.111");
$ar2 = array("service" => 9000, "network" => "222.222.222");
$ar3 = array("service" => 9500, "network" => "333.333.333");
$x = array("size" => 995,
        "data" => array($ar1,$ar2,$ar3));

$record = NULL;
$bus = 9000;

for($n = 0; $n < count($x["data"]); $n++){
    $checkService = $x["data"][$n];
    if($checkService["service"] == $bus){
        $record = $checkService["network"];
    }
}

if ($record) {
    // If record found:
    echo "Lookup Results for ".$bus.": ".$record;
    // Since we are searching for 9000 in this example, this should output -> Lookup Results for 9000: 222.222.222
} else {
    echo "Record not found";
}

This code could be simplified even further but I'm not sure what you need exactly.

You can check the end result through this example.

edited Apr 28, 2021 at 4:19

bad_coder

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answered Apr 1, 2019 at 21:33

Markafa Creative Solutions

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2 Comments

john_johnk Over a year ago

Thanks a lot Markafa, you are the only one who understood what I needed! Many thanks !

Markafa Creative Solutions Over a year ago

You're welcome. I'm glad I could help. Did it help you solve your problem though? Or do you need further explanation/assistance with your problem? @john_johnk

mahmoud nassar · Accepted Answer · 2019-04-01 20:55:29Z

-3

$found_record = NULL;
// let's assume $x as this array here
foreach($record in $x['data']){
if($record['service'] == $bus){
     $found_record = $record['service'];
      break;
    }
  }
 if($found_record){
   // record found
   var_dump($record);
  }else{
    echo "Not found";
}

answered Apr 1, 2019 at 20:55

mahmoud nassar

112 bronze badges

1 Comment

joka00 Over a year ago

Welcome to Stack Overflow! While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

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