How to remove characters from a str in python?

Question

I have the following str I want to delete characters.

For example:

from str1 = "A.B.1912/2013(H-0)02322" to 1912/2013

from srt2 = "I.M.1591/2017(I-299)17529" to 1591/2017

from str3 = "I.M.C.15/2017(I-112)17529" to 15/2017

I'm trying this way, but I need to remove the rest from ( to the right

newStr = str1.strip('A.B.')

'1912/2013(H-0)02322'

For the moment I'm doing it with slice notation

str1 = "A.B.1912/2013(H-0)02322"

str1 = str1[4:13]

'1912/2013'

But not all have the same length.

Any ideas or suggestions?

str1.split('(')[0] as a starter.

Klaus D.
– Klaus D.

2019-04-02 04:49:52 +00:00
Commented Apr 2, 2019 at 4:49 — Klaus D.
– Klaus D., Commented Apr 2, 2019 at 4:49

tegancp · Accepted Answer · 2019-04-02 05:08:32Z

2

With some (modest) assumptions about the format of the strings, here's a solution without using regex:

First split the string on the ( character, keeping the substring on the left:

left = str1.split( '(' )[0]   # "A.B.1912/2013"

Then, split the result on the last . (i.e. split from the right just once), keeping the second component:

cut = left.rsplit('.', 1)[1]  # "1912/2013"

or combining the two steps into a function:

def extract(s):
    return s.split('(')[0].rsplit('.', 1)[1]

answered Apr 2, 2019 at 5:08

tegancp

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Comments

gmds · Accepted Answer · 2019-04-02 04:49:10Z

1

Use a regex instead:

import re

regex = re.compile(r'\d+/\d+')

print(regex.search(str1).group())
print(regex.search(str2).group())
print(regex.search(str3).group())

Output:

1912/2013
1591/2017
15/2017

answered Apr 2, 2019 at 4:49

gmds

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Comments

Tim Biegeleisen · Accepted Answer · 2019-04-02 04:50:28Z

1

We can try using re.sub here with a capture group:

str1 = "A.B.1912/2013(H-0)02322"
output = re.sub(r'.*\b(\d+/\d+)\b.*', '\\1', str1)
print(output)

1912/2013

answered Apr 2, 2019 at 4:50

Tim Biegeleisen

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lmiguelvargasf · Accepted Answer · 2019-04-02 04:53:51Z

1

You have to use a regular expression to solve this problem.

import re

pattern = r'\d+/\d+'

str1 = "A.B.1912/2013(H-0)02322"
srt2 = "I.M.1591/2017(I-299)17529"
str3 = "I.M.C.15/2017(I-112)17529"

print(*re.findall(pattern, str1))
print(*re.findall(pattern, str2))
print(*re.findall(pattern, str3))

Output:

1912/2013
1591/2017
15/2017

answered Apr 2, 2019 at 4:53

lmiguelvargasf

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