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I am just wondering how to sort a NumPy array in descending order using NumPy sort() function efficiently. I checked the NumPy official documentation and StackOverflow question but I couldn`t able to find how to sort a NumPy array in descending order using the NumPy sort().

For instance:

import numpy as np
arr=np.array([1,5,8,4,5])
arr.sort()
print(arr)

Output:

[1,4,5,5,8]

I want to sort it by descending order, I understand after sorting the array in ascending order, I can reverse it like below.

arr.sort()[::-1]

But it creates a new array, Is it possible to sort descending without approaching this method?

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2
  • basically you want to reverse the array first and then sort arr[::-1].sort() Commented Apr 3, 2019 at 13:40
  • Flipping with [::-1] creates a view, not a copy. Commented Apr 3, 2019 at 13:45

1 Answer 1

Reset to default
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Using -np.sort(-arr):

import numpy as np
arr=np.array([1,5,8,4,5])
print(-np.sort(-arr))

OUTPUT:

[8 5 5 4 1]
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