Compare string to multiple strings in Python3

Question

I want to know if there is no text string in the variables. And then compare if there is another text string. The variables results It may contain the following: yes, no or ? I have follow code:

internet = result1
vpn = result2
zetas = result3

values = [internet, vpn, zetas]

    if any(v !== "?" for v in values):
        print("No exist ?")
    if any(v == "no" for v in values):
        print("Exist a NO")
    else:
        print("Good")

especially to see the most elegant way of doing this.

Can you please use some examples to demonstrate what you're trying to do and what the expected output is? — cs95
– cs95, Commented Apr 5, 2019 at 21:23
It looks like you are looking for elif. And also, there is no !==. Use == or !=. — zvone
– zvone, Commented Apr 5, 2019 at 21:23

furas · Accepted Answer · 2019-04-05 21:48:38Z

2

you can check value in list or value not in list

values = (internet, vpn, zetas)

if "?" not in values:
    print("No exist ?")
if "no"  in values:
    print("Exist a NO")
else:
    print("Good")

answered Apr 5, 2019 at 21:48

furas

149k12 gold badges121 silver badges171 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

gonmrm · Accepted Answer · 2019-04-05 21:33:46Z

1

First it is preferable to pass generator expressions instead of lists for loop feeding.

Secondly, although there can be many ways,, a good way would simply be:

values = (internet, vpn, zetas)
if "?" in (v for v in values):
  print("No exist ?")

Generator expressions save memory and time, not critical for the script in hand but useful for larger chunks of data.

answered Apr 5, 2019 at 21:33

gonmrm

891 silver badge6 bronze badges

5 Comments

furas Over a year ago

instead of (v for v in values) you can use values - if "?" in values:

gonmrm Over a year ago

That's right! But this way it will prevent "?" inside strings from escaping detection, I thought it would be a nice feature!

furas Over a year ago

(v for v in values) and values will work the same so there is no feature.

gonmrm Over a year ago

That's actually not correct. But you can try it.

python values = ["qwerty", "asdf"]  if "qwert" in values:    print('1')  if "qwert" in (v for v in values):    print('2')

You will see that it will print 2.

furas Over a year ago

My python print nothing for both versions. And this is correct result because there is no "qwert" on list ["qwerty", "asdf"]. If I use if "qwerty" in both versions then I see 1 and 2.

Rachel Gallen · Accepted Answer · 2019-04-05 22:50:35Z

I checked if the query you had regarding the question mark in inverted commas would escape detection using an array comparison [x in B for x in A]

#I assigned values to your variables to test
result1 ='?'
result2="no"
result3 = "yes"

internet = result1
vpn = result2
zetas = result3

#created an array with above values in it both in string format and as variable values (appended a number just for test)
A = [internet, 'no', '?', 'yes', vpn, zetas, '8']

#array of sample strings
B = ['?', 'no', 'yes']

exists = [x in B for x in A]
print (exists)

When the results of the comparison printed it gave: [True, True, True, True, True, True, False]. However if there were additional quote marks, e.g. '"?"' , the comparison on this printed as False. (Items in single quotes evaluate the same as double quotes..)

Feel free to run/re-assign values/test etc as you please. (might not be the answer you're looking for but hope it helps)

Collectives™ on Stack Overflow

Compare string to multiple strings in Python3

3 Answers 3

Comments

5 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

5 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related