How to replace a element in list of list using python3?
txt =[[""],[""],[""]]
for i in txt:
x = i.replace("", "apples")
print(x)
Expected Output:
apples
apples
apples
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2Possible duplicate of Replace values in list using Pythonawesoon– awesoon2019-04-08 06:06:46 +00:00Commented Apr 8, 2019 at 6:06
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i am asking for list of listpythoncoder– pythoncoder2019-04-08 06:08:23 +00:00Commented Apr 8, 2019 at 6:08
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You can just use an answer from the question I have linked and apply it to all elements in your list.awesoon– awesoon2019-04-08 06:09:30 +00:00Commented Apr 8, 2019 at 6:09
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4 Answers
To replace every instance of "" in the sublists of the main list txt, you can use the following list-comprehension:
txt =[[""],[""],[""]]
txt = [[x if not x=="" else 'apples' for x in sublist] for sublist in txt]
which produces:
[['apples'], ['apples'], ['apples']]
The code you have right now cannot work because given the way you loop over txt, i is the sublist and you python list objects do not have a .replace method.
Comments
def replace(value, new_value, outer_list):
for inner_list in outer_list:
for i,element in enumerate(inner_list):
if element == value:
inner_list[i]= new_value
return outer_list
txt =[[""],[""],[""]]
txt = replace("", "apple", txt)
This function could do your need
Comments
Try this one:
txt = [[""],[""],[""]]
for i in range(len(txt)):
for ii in range(len(txt[i])):
txt[i][ii] = (txt[i][ii]).replace("","apples")
print(txt)
Comments
Using list comprehension:
txt =[[""],[""],[""]]
print([[x if x != "" else 'apples' for x in sub] for sub in txt])
OUTPUT:
[['apples'], ['apples'], ['apples']]
To print them separately;
txt = [[x if x != "" else 'apples' for x in sub] for sub in txt]
for sub in txt:
for elem in sub:
print(elem)
OUTPUT:
apples
apples
apples
