I have a list l1 =[1,56,67,79,90,47,08,56,79,84,76,79,68,]
Now, I want to print indices 4,6,9,10 alone using a loop
I tried:
for i in l1:
Print(i[4]..)
But it says: int is not subscriptable
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Why do you need the for loop?Sayse– Sayse2019-04-10 17:58:34 +00:00Commented Apr 10, 2019 at 17:58
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Possible duplicate of How to print multiple non-consecutive values from a list with Python 3.5.1user8060120– user80601202019-04-10 18:04:09 +00:00Commented Apr 10, 2019 at 18:04
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It was the task given brovittaldev anderson– vittaldev anderson2019-04-11 02:02:14 +00:00Commented Apr 11, 2019 at 2:02
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2 Answers
if you just want to loop over all items in the list by the indexes you could do something like this:
l1 =[1,56,67,79,90,47,8,56,79,84,76,79,68]
for i in range(len(l1)):
if i in (4, 6, 9, 10):
print(l1[i])
that being said, this is not the most efficient thing
1 Comment
perennial_noob
Yeah this works too although my only comment on this approach is that it is better to use a named list than use a tuple for maintainability,
I am assuming this is for a homework and so you want to use loops for this.
When you say i in l1 each element i is an int and so it won't work to index it.
If you are trying to specifically print elements in indexes 4, 6, 9, 10 then you need to put these in a list and iterate over these. So for ex:
l1 =[1,56,67,79,90,47,08,56,79,84,76,79,68,]
to_print = [4, 6, 9, 10] # So if you want to print other/more index positions then modify this. Note that you may want to do a length check too before using these indexes as is.
for i in to_print:
print(l1[i])
3 Comments
vittaldev anderson
Tkz alot got😊 it helped me
vittaldev anderson
How to do tht i m new here
perennial_noob
Oh on the left side of the answer below the score you'll see a check mark. Click on it to mark as accepted.
