Python & Sorting : Sorting Elements In Order Their Subelements in an Array

Question

I have an array and it has 4 elements and every element has 3 subelements;

myList = [['26.03.2019', 'Michelle', '8'], ['03.04.2019', 'Jack', '2'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8']]

As you see, every elements' first subelement is a date. And I want to order these elements with their dates. So I want that output when I enter print(myList);

[['26.03.2019', 'Michelle', '8'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8'], ['03.04.2019', 'Jack', '2']]

How can I do that? Can you give me a solution for this?

Ma0 · Accepted Answer · 2019-04-11 09:31:33Z

1

print(myList) would just print your list. You do not want to fiddle with that. What you want to do is sort your list prior to printing. Like so for example:

import datetime


myList = [['26.03.2019', 'Michelle', '8'], ['03.04.2019', 'Jack', '2'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8']]
myList.sort(key=lambda sublist: datetime.datetime.strptime(sublist[0], "%d.%m.%Y"))

print(myList)  # -> [['26.03.2019', 'Michelle', '8'], 
               #     ['01.04.2019', 'George', '2'], 
               #     ['02.04.2019', 'Micheal', '8'], 
               #     ['03.04.2019', 'Jack', '2']]

Note that doing myList.sort(..) permanently changes your list.. If that is not what you want, you can create a new one using sorted as @Rakesh proposes in his answer.

Kudos: the code for the sorting of the dates was taken from here

answered Apr 11, 2019 at 9:31

Ma0

15.2k4 gold badges38 silver badges70 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Rakesh · Accepted Answer · 2019-04-11 09:31:09Z

1

Convert string date to datetime object and then use sorted

Ex:

import datetime
myList = [['26.03.2019', 'Michelle', '8'], ['03.04.2019', 'Jack', '2'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8']]

print( sorted(myList, key=lambda x: datetime.datetime.strptime(x[0], "%d.%m.%Y")) )

Output:

[['26.03.2019', 'Michelle', '8'],
 ['01.04.2019', 'George', '2'],
 ['02.04.2019', 'Micheal', '8'],
 ['03.04.2019', 'Jack', '2']]

answered Apr 11, 2019 at 9:31

Rakesh

82.9k17 gold badges85 silver badges122 bronze badges

Comments

Devesh Kumar Singh · Accepted Answer · 2019-04-11 09:31:41Z

1

Sort your list on the date string, after changing it to datetime object via strptime

import datetime
myList = [['26.03.2019', 'Michelle', '8'], ['03.04.2019', 'Jack', '2'], ['01.04.2019', 'George', '2'], ['02.04.2019', 'Micheal', '8']]

myList.sort(key=lambda x: datetime.datetime.strptime(x[0], "%d.%m.%Y"))
print(myList)
#[
#['26.03.2019', 'Michelle', '8'], 
#['01.04.2019', 'George', '2'], 
#['02.04.2019', #'Micheal', '8'], 
#['03.04.2019', 'Jack', '2']
#]

answered Apr 11, 2019 at 9:31

Devesh Kumar Singh

20.5k5 gold badges25 silver badges43 bronze badges

Collectives™ on Stack Overflow

Python & Sorting : Sorting Elements In Order Their Subelements in an Array

3 Answers 3

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related