How to concatenate Integers and strings in python

Question

I am trying to search for a substring with the specify pattern using re library. I wrote a function to do that but end up getting this error: Type Error: cannot concatenate str and integers. Below is my function;

def searchValue(obs, concept):
try:
    found = re.search('## !!'concept+'=(.+?)!! ##',obs)
except AttributeError:
    found = 'null'
return found

obs= '!!1834=7850!! ## !!1915=Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.!! ## !!1915=Patient is HIV positive since 2016,no presents with pains on the plantar surface and pelvic pain.!! ## !!5096=2013-07-29!! ## !!5219=1068!! ## !!6504=7189!! ## !!6509=6511!! ## !!6575=1107!! ## !!6605=1065!! ## !!7191=MELANOMA OF THE RIGHT HEEL.!! ## !!8723=5622!!'
bett = searchValue(obs, 1915)

print(bett)

Any help will be appreciated.

For this code you should get SyntaxError (missing + before concept). — CristiFati
– CristiFati, Commented Apr 12, 2019 at 13:17
As @CristiFati pointed out you are getting that error because you need to do '## !!'+concept+'=(.+?)!! ##'. Python is trying to concat "str1""str2" <-- valid python syntax. But in your case "str2" is an int which is why it errored. — Error - Syntactical Remorse
– Error - Syntactical Remorse, Commented Apr 12, 2019 at 13:46

Lante Dellarovere · Accepted Answer · 2019-04-12 13:22:23Z

1

If you are not interested in substrings position I'd use:

def searchValue(obs, concept):
    return re.findall('## !!'+ str(concept) + '=(.+?)!! ##',obs)

bett = searchValue(obs, 1915)
print(bett)

>>> ['Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.']

answered Apr 12, 2019 at 13:22

Lante Dellarovere

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Comments

borcabar · Accepted Answer · 2019-04-12 13:49:39Z

after some wortk on your code i got something that seems fine; if not let me know.

The important part is to feed the re.search() with a complete string; that's done using .format().

Greetings


def searchValue(obs, concept):
    try:
        expression = '## !!{0}=(.+?)!! ##'.format(concept)
        found = re.search(expression, obs)
    except AttributeError:
        found = 'null'
    return found

obs= '!!1834=7850!! ## !!1915=Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.!! ## !!1915=Patient is HIV positive since 2016,no presents with pains on the plantar surface and pelvic pain.!! ## !!5096=2013-07-29!! ## !!5219=1068!! ## !!6504=7189!! ## !!6509=6511!! ## !!6575=1107!! ## !!6605=1065!! ## !!7191=MELANOMA OF THE RIGHT HEEL.!! ## !!8723=5622!!'
bett = searchValue(obs, 1915)

print(bett)

CristiFati · Accepted Answer · 2019-04-12 13:53:47Z

There are 2 errors in your code:

Missing a + in '## !!'concept (might be a typo?) - yielding syntactically incorrect code (SyntaxError)
Adding strings (`'## !!') with ints (1915) - which is not possible (TypeError). You have to convert the int to str

Here's how your pattern (re.search's 1^st argument) should look like (quickest way, of course there's room for improvements):

>>> concept = 1915
>>> obs = '!!1834=7850!! ## !!1915=Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.!! ## !!1915=Patient is HIV positive since 2016,no presents with pains on the plantar surface and pelvic pain.!! ## !!5096=2013-07-29!! ## !!5219=1068!! ## !!6504=7189!! ## !!6509=6511!! ## !!6575=1107!! ## !!6605=1065!! ## !!7191=MELANOMA OF THE RIGHT HEEL.!! ## !!8723=5622!!'
>>>
>>> found = re.search('## !!' + str(concept) + '=(.+?)!! ##', obs)  # !!! Copy / paste this in your code
>>>
>>> found
<re.Match object; span=(14, 110), match='## !!1915=Patient is awaiting imaging results, th>
>>> found.group()
'## !!1915=Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.!! ##'

noobie · Accepted Answer · 2019-04-12 13:18:21Z

0

You are trying to concatenate a string with integer type that's why you are getting the error. try using this and do share if it solves your problem:

bett = searchValue(obs, str(1915))

also add the + sign before concept as suggested by @CristiFati

answered Apr 12, 2019 at 13:18

noobie

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Comments

user11111136 · Accepted Answer · 2019-04-12 13:19:03Z

You missed a +. You also need to make the integer that you are trying to concatenate (concept) a string because you cannot concatenate integers with strings. You must also make the 1915 you are searching for in the 'obs' variable a string because 'obs' is a string not an integer.

def searchValue(obs, concept):
try:
    found = re.search('## !!' + str(concept) + '=(.+?)!! ##',obs)
except AttributeError:
    found = 'null'
return found

obs= '!!1834=7850!! ## !!1915=Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.!! ## !!1915=Patient is HIV positive since 2016,no presents with pains on the plantar surface and pelvic pain.!! ## !!5096=2013-07-29!! ## !!5219=1068!! ## !!6504=7189!! ## !!6509=6511!! ## !!6575=1107!! ## !!6605=1065!! ## !!7191=MELANOMA OF THE RIGHT HEEL.!! ## !!8723=5622!!'
bett = searchValue(obs, str(1915))

print(bett)

butterflyknife · Accepted Answer · 2019-04-12 13:19:41Z

0

I think you mean:

    found = re.search('## !!' + concept + '=(.+?)!! ##',obs)

The correct version is:

    found = re.search('## !!' + str(concept) + '=(.+?)!! ##',obs)

You have to cast from int to string explicitly.

answered Apr 12, 2019 at 13:19

butterflyknife

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Comments

Sundeep · Accepted Answer · 2019-04-12 13:20:12Z

Your code is correct but you are missing a + for concat

def searchValue(obs, concept):
try:
    found = re.search('## !!'+str(concept)+'=(.+?)!! ##',obs)
except AttributeError:
    found = 'null'
return found

obs= '!!1834=7850!! ## !!1915=Patient is awaiting imaging results, then start darcabazine 250 ml every 21 days.!! ## !!1915=Patient is HIV positive since 2016,no presents with pains on the plantar surface and pelvic pain.!! ## !!5096=2013-07-29!! ## !!5219=1068!! ## !!6504=7189!! ## !!6509=6511!! ## !!6575=1107!! ## !!6605=1065!! ## !!7191=MELANOMA OF THE RIGHT HEEL.!! ## !!8723=5622!!'
bett = searchValue(obs, 1915)

print(bett)

Make sure you convert the integer value to string and pass so that it considers it as a string or convert it using str(Integer)

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