Convert a list of strings to a list of strings and ints

Question

I have a dictionary of lists, each list has 3 elements, i want to convert the 2nd and 3rd element to ints from strings

dict = {1:['string', '2', '3',],
        2:['string', '2', '3',],
        3:['string', '2', '3',],}

to become:

dict = {1:['string', 2, 3,],
        2:['string', 2, 3,],
        3:['string', 2, 3,],}

Thank you

Diptangsu Goswami · Accepted Answer · 2019-04-17 12:40:17Z

3

Firstly, don't name your dictionaries dict, as it's a reserved keyword and you don't wanna overwrite it.

Coming to your solution.

d = {
    1: ['string', '23', '3'],
    2: ['string', '2', '3'],
    3: ['string', '2', '3'],
}


d2 = {
    k: [
        int(i) if i.isdigit() else i 
        for i in v
    ] 
    for k, v in d.items()
}

Will give you an output of:

{   
    1: ['string', '23', '3'], 
    2: ['string', '2', '3'], 
    3: ['string', '2', '3']
}
{
    1: ['string', 23, 3], 
    2: ['string', 2, 3], 
    3: ['string', 2, 3]
}

edited Apr 17, 2019 at 12:40

Diptangsu Goswami

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answered Apr 17, 2019 at 6:48

Shuvojit

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1 Comment

Cloudomation Over a year ago

Caution: This solution will also convert the first element of the list to an integer when it contains only digits! This was not requested by OP

Cloudomation · Accepted Answer · 2019-04-17 12:54:41Z

0

If you dictionary has many elements you might not want to create a second dictionary in memory, but modify the existing one in-place:

data = {
    1: ['string', '2', '3'],
    2: ['string', '2', '3'],
    3: ['string', '2', '3'],
}

for v in data.values():
    v.append(int(v.pop(1)))
    v.append(int(v.pop(1)))

print(data)

Output:

{1: ['string', 2, 3], 2: ['string', 2, 3], 3: ['string', 2, 3]}

answered Apr 17, 2019 at 12:54

Cloudomation

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