How to compare an array variable and Normal variable using if condition in PHP

Question

I want to compare an array variable and Normal variable using if condition in PHP.. I have an Array VAriable as .$AllowedEnquiryType[$i] and a variabe as $TIntType how to check these to are equal.

My coding is

for($i=1;$i<=$length;$i++)
    {
        if($AllowedEnquiryType[$i]==$TIntType) 
        {   
             return true;
        }
        else
        {

            return false;
        }
}

Dont see any problem too. Maybe, that it just compares only the first element? Thats because you return from the method/function/file right at the first iteration. Also usually arrays begin with 0 (not 1) and the last element is $length -1 and not $length. — KingCrunch
– KingCrunch, Commented Apr 7, 2011 at 10:47

Pascal MARTIN · Accepted Answer · 2011-04-07 11:04:44Z

2

Well, if you want to check if $AllowedEnquiryType[$i] and $TIntType are equal, you already wrote what to do :

if ($AllowedEnquiryType[$i] == $TIntType) {
    // those are equal
}

Else, if you want to check if all items of $AllowedEnquiryType are equal to $TIntType, you could do something like this :

$allEqual = true;
for($i=1;$i<=$length;$i++) {
    if ($AllowedEnquiryType[$i] != $TIntType) {
        $allEqual = false;
        break;  // no need to check the other items
    }
}

if ($allEqual) {
    // all items in $AllowedEnquiryType are equal to $TIntType
}

edited Apr 7, 2011 at 11:04

answered Apr 7, 2011 at 10:46

Pascal MARTIN

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1 Comment

Stefan Gehrig Over a year ago

Perhaps add a little break; inside the if-statement... Just to make sure we bail out of the loop if further processing is not required any more.

Bhanu Prakash Pandey · Accepted Answer · 2011-04-07 10:46:28Z

0

use in_array

link

answered Apr 7, 2011 at 10:46

Bhanu Prakash Pandey

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Comments

Emmerman · Accepted Answer · 2011-04-07 11:24:08Z

0

Yes, you can use if($AllowedEnquiryType[$i]==$TIntType). What exactly are you asking for?

answered Apr 7, 2011 at 11:24

Emmerman

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