Sort Array element by its values

Question

I have an array elements which need to sort and make selected element into top of array.

[{
    parent_email: '[email protected]',
    id: 143,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 210,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 225,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 221,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 224,
    unreadCount: 0 
 }]

i have another array by which above array element need to sort. first element is on top second is on second position third is on third position and so on.

[{ 
    parent_id: '[email protected]'
 },
 { 
    parent_id: '[email protected]'
 },
 { 
    parent_id: '[email protected]'
 }]

my result array should be like

[{
    parent_email: '[email protected]',
    id: 221,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 225,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 210,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 143,
    unreadCount: 0 
 },
 {
    parent_email: '[email protected]',
    id: 224,
    unreadCount: 0 
 }]

i have tried but it only sort single element not more then one.

for (var i = array2.length - 1; i >= 0; i--) {
array1.sort(function(x,y){
    return x.parent_email == rows[i].parent_id ? -1 : y.parent_email ==  rows[i].parent_id ? 1 : 0; 
    });
}

Jonas Wilms · Accepted Answer · 2019-04-24 07:17:26Z

2

You should sort the first array by the index in the second array:

 const emailRank = new Map();
 for(const [index, { parent_id }] of array2.entries())
   emailRank.set(parent_id, index);

 array1.sort((a, b) => emailRank.get(b.parent_email) - emailRank.get(a.parentEmail));

answered Apr 24, 2019 at 7:17

Jonas Wilms

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Yevhen Horbunkov · Accepted Answer · 2019-04-24 07:29:31Z

To me it seems not exactly like sorting (as you grab matching items in desired order and don't care about the order of the rest), so you may go, like (though, it may produce unexpected output in case of duplicating e-mails):

const src = [
  {parent_email: '[email protected]', id: 221, unreadCount: 0},
  {parent_email: '[email protected]', id: 225, unreadCount: 0},
  {parent_email: '[email protected]', id: 210, unreadCount: 0},
  {parent_email: '[email protected]', id: 143, unreadCount: 0},
  {parent_email: '[email protected]', id: 224, unreadCount: 0}
];
const order = [
  {parent_id: '[email protected]'},
  {parent_id: '[email protected]'},
  {parent_id: '[email protected]'}
];
const res = order
  .map(item => src.find(entry => entry.parent_email == item.parent_id))
  .concat(src.filter(entry => !order.map(item => item.parent_id).includes(entry.parent_email)));

console.log(res);

.as-console-wrapper {
  max-height: 100% !important;
  top: 0;
}

Atchutha rama reddy Karri · Accepted Answer · 2019-04-24 07:18:55Z

0

Try sort in lodash

_.sortBy( parent_email, [function(o) { return o.parent_email; }]);

answered Apr 24, 2019 at 7:18

Atchutha rama reddy Karri

1,56915 silver badges16 bronze badges

2 Comments

Manuel Spigolon Over a year ago

beware, you are not using the array with parent_id

Atchutha rama reddy Karri Over a year ago

i am just giving info. just change it for Parent_id if you want it

William Leung · Accepted Answer · 2019-04-24 07:52:18Z

const data = [{
    parent_email: '[email protected]',
    id: 143,
    unreadCount: 0
  },
  {
    parent_email: '[email protected]',
    id: 210,
    unreadCount: 0
  },
  {
    parent_email: '[email protected]',
    id: 225,
    unreadCount: 0
  },
  {
    parent_email: '[email protected]',
    id: 221,
    unreadCount: 0
  },
  {
    parent_email: '[email protected]',
    id: 224,
    unreadCount: 0
  }
]
const orderBy = [{
    parent_id: '[email protected]'
  },
  {
    parent_id: '[email protected]'
  },
  {
    parent_id: '[email protected]'
  }
]
const length = data.length
const dataOrders = orderBy.reduce((result, item, index) => (result[item.parent_id] = index + 1) && result, {})
const dataOrdered = data.sort((a, b) => (dataOrders[a.parent_email] || length) - (dataOrders[b.parent_email] || length))
console.log(dataOrdered)

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