How to save a fetched JSON in a variable [node-fetch]

Question

I have the following code , which logs the json if I use a console.log, but I want to save it in the jsonBlocks variable. But it won't work. I guess its because of async stuff, but I cant find a way to solve it.

var jsonBlocks;


fetch('https://myurl')
    .then(res => res.text())
    .then(body => this.jsonBlocks = body )

Whatever you want to do with the data, you have to do it after the async function has finished. You're probably trying to do this too early, while the fetch is still running. We need to see more code to provide help though. — user5734311
– user5734311, Commented Apr 25, 2019 at 11:06
Why are using this befor jsonBlock which is defined with var at the begining of the file? — DSCH
– DSCH, Commented Apr 25, 2019 at 11:06
Possible duplicate of How do I return the response from an asynchronous call? — user5734311
– user5734311, Commented Apr 25, 2019 at 11:07

1565986223 · Accepted Answer · 2019-04-26 18:11:28Z

3

You can use async..await for the particular piece of code like:

async function getBlock() {
  let jsonBlocks;
  try {
    var response = await fetch('https://myurl');
    jsonBlocks = await response.text();
    console.log(jsonBlocks)
  } catch (e) {
    // handle error
    console.error(e)
  }
}

getBlock()

If you return anything from getBlock, it'll be wrapped in Promise.

answered Apr 26, 2019 at 18:11

1565986223

6,7483 gold badges24 silver badges34 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to save a fetched JSON in a variable [node-fetch]

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related